Subtraction of a Vector
Trending Questions
A swimmer wishes to cross a 500 m wide river flowing at 5 km/h. His speed with respect to water is 3 km/h.
(a) If he heads in a direction making an angle (\theta\) with the flow, find the time he takes to cross the river.
(b) Find the shortest possible time to cross the river.
- 1200 m
- 1300 m
- 1400 m
- 1500 m
- 22.36 km
- 5 km
- 2 km
- 20 km
The magnitudes of vectors →A, →Band→C are 3, 4 and 5 units respectively. If →A+→B=→C, the angle between →A and →B is
tan−1(75)
π2
cos−1(0.6)
π4
A plane is revolving around the earth with a speed of 100 km/hr at a constant height from the surface of earth. The change in the velocity as it travels half circle is
200 km/hr
0
150 km/hr
100√2km/hr
What is the angle between →P and the resultant of (→P+→Q) and (→P−→Q)
Zero
tan−1(PQ)
tan−1(QP)
tan−1(P−QP+Q)
A scooter going due east at 10ms−1 turns right through an angle of 90°. If the speed of the scooter remains unchanged in taking turn, the change is the velocity of the scooter is
Zero
10.0ms−1 in southern direction
20.0ms−1 south eastern direction
14.14ms−1 in south-west direction
- ^j−^k
- ^i+^j+^k
- ^i+^j−^k
- ^j+^k
If Sameer moves from point A having position vector 3^i+2^j+5^k to point B having position vector 6^i+3^j+7^k, what is his displacement vector?
3^i+^j+3^k
3^i+^j+2^k
3^i+^j+4^k
3^i+^j+7^k
- (1+√3)^i+2^j
- (1+√3)^i−2^j
- (1−√3)^i+2^j
- (1−√3)^i
A park has a radius of 10 m. If a vehicle goes round it at an average speed of 18 km/hr, what should be the proper angle of banking ?
- 3^i+4^j
- 0
- 4^i+5^j
- 4^i+3^j
- ^i−^j
- −^i−^j
- 1√2^i−1√2^j
- −1√2^i−1√2^j
- 10^i
- 0
- 10^i+10^j
- 10^j
- 3^i+^j−3^k
- 4^i+4^j+^k
- 4^i−4^j−^k
- 3^i−^j+3^k
- P =2Q
- P =Q
- PQ=1
- None of these
- 0
- 5^i+5^j
- 5^j
- 5^i
- 20m East
- 20m West
- 20m North
- 20m South
- 20√2 m/s N−W
- 40 m/s N−W
- 40 m/s S−W
- 20√2 m/s S−W
A plane is revolving around the earth with a speed of 100 km/hr at a constant height from the surface of earth. The change in the velocity as it travels half circle is
200 km/hr
150 km/hr
100√2km/hr
0
The resultant of →P and →Q is perpendicular to →P. What is the angle between →Pand→Q
cos−1(PQ)
sin−1(PQ)
cos−1(−PQ)
sin−1(−PQ)
- 13^i+^j−26^k
- 13(^i+^j+^k)
- 26(^i+^k)
- 13(2^j+^k)
- 50√2 km/hr north-west
- 50√2 km/hr south-west
- 50 km/hr south-west
- 50 km/hr north-west
- 0
- 5^i+5^j
- 5^j
- 5^i
θ(t)=tan−1v0y−gtv0x
- 2
- 3
- 4
- More than 4
- Velocity of A relative to B is −32^i−44^j
- Position of A relative to B as a function of time is given by →rAB=(3−32t)^i+(4−44t)^j
- Velocity of A relative to B is 32^i−44^j
- Position of A relative to B as a function of time is given by (32t^i−44t^j)
- P2+Q2
- 4PQ
- 2(P2−Q2)
- 2(P2+Q2)