Using Lenz's Law
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A conducting square frame of side ‘a’ and along straight wire carrying current I are located in the same plane a shown in the figure. The fame moves to the right with constant velocity ‘v’. The emf induced in the frame will be proportional to:
1x2
1(2x−a)2
1(2x+a)2
1(2x−a)(2x+a)
- shape of the loop.
- area of the loop.
- number of turns in the loop.
- strength of the current.
A length L of wire carries a steady current I. It is bent first to form a circular plane coil of one turn. The same length is now bent more sharply to give a double loop of smaller radius. The magnetic field at the centre caused by the same current is
[NCERT 1980
- A quarter of its first value
Unaltered
- A half of its first value
Four times of its first value
- more than g
- equal to g
- less than g
- Data not sufficient to predict
A coil having 500 square loops each of side 10 cm is placed normal to a magnetic field which increases at the rate of 1 T s^−1. The induced emf. is?
0.1V
5.0V
0.5V
1.0V
- stationatry charge
- moving charge
- a positive charge only
- a negative charge only
If the magnetic field is parallel to a surface then the magnetic flux through the surface is
infinite
small but not zero
zero
large but not infinite
Magnetic fields at two points on the axis of a circular coil at a distance of and from the center are in the ratio. The radius of coil is ______
- 40 V
- 140 V
- – 40 V
- 300 V
A straight line conductor of length 0.4 m is moved with a speed of 7 m/s perpendiculars to a magnetic field of intensity 0.9 Wb/m2.
The induced e.m.f. across the conductor is
(a) 5.04 V
(b) 25.2 V
(c) 1.26 V
(d) 2.52 V
- 8 ms−1
- 5.5 ms−1
- 20 ms−1
- 40 ms−1
- BRA
- ABR
- ABR
- B2AR2
- X==A.=B
- X=¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯A+B
- X=A.B
- X=¯¯¯¯¯¯¯¯¯¯¯A.B
The total charge induced in a conducting loop when it is moved in magnetic field depends on
The rate of change of magnetic flux
Initial magnetic flux only
The total change in magnetic flux
Final magnetic flux only
- 6 Watt
- 2 Watt
- 3 Watt
- 5 Watt
- the current through R1 decreases with time t
- the potential drop across L increases with t
- the magnetic energy stored in the steady state equals 12LE2R22
- the total current through the battery is, in the steady state, ER1+ER2
(b) A horizontal conducting rod 10 m long extending from east to west is falling with a speed 5.0 ms−1 at right angles to the horizontal component of the Earth's magnetic field, 0.3×10−4Wb m−2. Find the instantaneous value of the emf induced in the rod.
(given c=3×108 ms−1 & electron charge =1.6×10−19 C)
- 3.2×10−18 N
- 2.4×10−18 N
- 4.8×10−19 N
- 1.6×10−19 N
A copper ring is held horizontally and a bar magnet is dropped through the ring with its length along the axis of the ring. Then, the acceleration of the falling magnet (neglect air resistance) will be
g
more than g
less than g
zero
The direction of the magnetic field due to a current-carrying conductor can easily be found by using left hand thumb rule.
- True
- False
- Equal to g
- More than g
- Less than g
- Sometimes less and sometimes more than g
- 0.105 V
- 0.01V
- 0.205V
- 1.2 V
- Anticlockwise
- Clockwise
- East
- West
4×10−6 Vm−1
- 7.5×10−6 Vm−1
- 1.33×10−2 Vm−1
- 3.33×10−9 Vm−1
Can you have negative EMF
The magnitude of the earths magnetic field at a place and the angle of dip is. A horizontal conductor of length lying along the magnetic North-South moves Eastwards with a velocity v, the emf induced across the conductor is
zero
In an electromagnetic induction, what is the source of electric energy that causes induced current?