Variation of Intensity in Space
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Two coherent narrow slits emitting sound of wavelength λ in the same phase are placed parallel to each other at a small separation of 2λ. The sound is detected by moving a detector on the screen E at a distance D(>>λ) from the slit S, as shown in figure (16-E6). Find the distance x such that the intensity at P is equal to the intensity at O.
- 12 m
- 5 m
- 2 m
- 3 m
- 50%
- 30%
- 40%
- 36%
- λ
- 2λ
- 4λ
- λ/2
- n1>n2>n3
- n2>n1>n3
- n1=n2>n3
- n2>n3>n1
- Remains constant
- 1r3
- 1r
- 1r2
- 16 :4
- 4 :2
- 100 :64
- 10 :8
- 45
- 54
- 2516
- 1625
Two cars and are moving away from each other in opposite directions. Both the cars are moving at a speed of with respect to the ground. If an observer in car detects a frequency of of the sound coming from car , what is the natural frequency of the sound source in car ? (speed of sound in air )
[Assume, air density is 1.3 kg/m3 and velocity of sound is 330 m/s and take log101.86=0.269]
- 2×10−12 W/m2, 1 dB
- 1.86×10−12 W/m2, 1.6 dB
- 1.86×10−12 W/m2, 2.7 dB
- 2×10−12 W/m2, 2.7 dB
- 7.5×107 meter /second
- 6×108 meter /second
- 1.5×108 meter /second
- 3×108 meter /second
- β=a−br2
- β=a−b (logr)2
- β=a−blogr
- β=−b logr2
- 1
- 2
- 4
- 8
- D=λ2
- D=15λ12
- D=15λ4
- D=λ3
A sound made on the surface of a lake takes to reach a boatman. How much time will it take to reach a diver inside the water at the same depth?
Velocity of sound in air
Velocity of sound in water
- 35.2×10−12 J/m3
- 35.2×10−11 J/m3
- 35.2×10−10 J/m3
- 35.2×10−13 J/m3
Number of waves of orange light emitted by krypton in 1 m is ____________.
- 0:1:4
- 2:1:0
- 0:1:2
- 4:1:0
- 50√2−1 m
- 50√2 m
- 100√2 m
- 50√2√2−1 m
- 62.3 Hz
- 30 Hz
- 45.3 Hz
- 50 Hz
- wave number k
- frequency v
- wave speed V
- angular frequency ω
- y=4sin[ω(t−2)−k(x−4)+π6]
- y=4sin[ω(t+2)+k(x)+π6]
- y=4sin[ω(t−2)−k(x−4)+5π6]
- y=4sin[ω(t+2)+k(x−2)+π6]