Velocity of a Point
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A rod of mass m and length L, lying horizontally, is free to rotate about a vertical axis through its centre. A horizontal force of constant magnitude F acts on the rod at a distance of L4 from the centre. The force is always perpendicular to the rod. Find the angle rotated by the rod during the time l after the motion starts.
A slender uniform rod of mass M and length L is pivoted at one end so that it can rotate in a vertical plane (see the figure).
There is negligible friction at the pivot. The free end is held vertically above the pivot and then released. The angular acceleration of the rod when it makes an angle θ with the vertical, is
2g3l sin θ
3g2l cos θ
2g3l cos θ
3g2lsin θ
- →VC−→VA=2(→VB−→VC)
- →VC−→VB=→VB−→VA
- |→VC−→VA|=2|→VB−→VC|
- |→VC−→VA|=4|→VB|
- Speed of point A is vA=ω0R
- Speed of point B is zero.
- Speed of point C is vC=ω0R2
- Speed of point C is vC=ω0R
- 3
- 1
- None of these
- 1/3
- vcos(θ2)
- v(1+cosθ)
- 2vcos(θ2)
- v(1+sinθ)
A hollow sphere is released from the top of an inclined plane of inclination θ. (a) What should be the minimum coefficient of friction between the sphere and the plane to prevent sliding ? (b) Find the kinetic energy of the ball as it moves down a length l on the incline if the friction coefficient is half the value calculated in part (a).
- π3
- π6
- 23π
- π2
- 4^i+3^j
- 4^i−3^j
- −3^i+4^j
- −4^i−3^j
- v
- 2v
- v√2
- √2v
- vQ>vP>vC
- vQ=vP, vC=12vP
- vQ>vC>vP
- vQ<vC<vP
A small particle of mass m is given an initial high velocity in the horizontal plane and winds its cord around the fixed vertical shaft of radius a. Motion occurs essentially in horizontal plane (assume gravity free space). The angular velocity of the cord is ω0 when the distance from the particle to the tangency point is r0.
The angular velocity of the cord after it has turned through an angle is
The angular velocity of the cord after it has turned through an angle is
The KE of the particle will increase
The KE of the particle will remain same
- vQ>vP>vC
- vQ<vC<vP
- vQ=vP, vC=12vP
- vQ>vC>vP
Choose the correct option.
- Velocity of point A w.r.t point B will always remain constant.
- Speed of point A w.r.t point B will always remain constant.
- Magnitude of relative velocity of point A w.r.t point B is 2ω|→rAB| m/s.
- None of these.
- ωr3
- ωr
- ω2r
- ωr2
If acceleration of COM (O) is ao=2 m/s2 and acceleration of point A is aA=6 m/s2, then find angular acceleration α.
- 4 rad/s2
- 6 rad/s2
- 2 rad/s2
- 1 rad/s2
The linear speed of end A just before striking the ground is
- √3gL10(5−√3)
- √3gL10(5+√3)
- √3g10L(5−√3)
- √3g10L(5+√3)
- 2.0 m
- 10.0 m
- 1.0 m
- 20.0 m
- There is no relative motion at the point of contact between wheel and ground.
- Wheel will perform pure rolling if velocity of point P is zero.
- Vcm=ωR
- None of these
Choose the correct option(s):
- The speed of point B is 2V
- The speed of points C, A and D is equal to V
- The speed of point A is zero and speed of point C is √2V
- The speed of point O is less than the speed of C.
Suppose a and α be the magnitudes of linear and angular acceleration due to friction. Then match the statements in Column I with statements in column II
Column IColumn II(A)When V=Rω(p) a=Rα(a≠0)(B)When V=Rω2(q) a>Rα(C) When V=2Rω(r) a<Rα(s)None of these
- A→(p), B→(r), C→(r)
- A→(q), B→(t), C→(p)
- A→(s), B→(r), C→(r)
- A→(s), B→(r), C→(s)
A circular disc of mass 300 gm and radius 20 cm can rotate freely about a vertical axis passing through is center O. A small insect of mass 100 gm is initially at a point A on the rim. The insect initially stationary starts walking from rest along the rim of disc with such a time varying relative velocity that the disc rotates in the opposite direction with a constant angular acceleration = 2πrad/s2. After some time T, the insect is back at the point A
. What is the time taken by insect to reach the original position?