Wave on a String
Trending Questions
Q. If the initial tension on a stretched string is doubled, then the ratio of the initial and final speeds of a transverse wave along the string is:
- 1:2
- √2:1
- 1:1
- 1:√2
Q. A wave travelling along a string is described by y(x, t)=0.008sin(85x−4t) in SI units, where x is in metres and t is in seconds . Calculate the wavelength and frequency of the wave.
- 8.4 cm, 1 Hz
- 14.8 cm, 0.64 Hz
- 7.4 cm, 1.28 Hz
- 7.4 cm, 0.64 Hz
Q. Wave pulse on a string shown in figure is moving to the right without changing shape. Consider two particles at positions x1=1.5 m and x2=2.5 m. Their transverse velocities at the moment shown in figure are along directions.
- positive y-axis and positive y-axis, respectively
- negative y-axis and y-axis, respectively
- negative y-axis and negative y-axis, respectively
- positive y-axis and negative y-axis, respectively
Q.
Two waves, each having a frequency of 100 Hz and a wavelength of 2.0 cm, are travelling in the same direction on a string. What is the phase difference between the waves (a) if the second wave was produced 0.015 s later than the first one at the same place, (b) if the two waves were produced at the same instant but the first one was produced a distance 4.0 cm behind the second one ? (c) If each of the waves has an amplitude of 2.0 mm, what would be the amplitudes of the resultant waves in part (a) and (b) ?
Q. A 200 Hz sinusoidal wave is travelling in the positive x-direction along a string with a linear mass density of 4×10−3 kg/m and a tension of 40 N. At time t=0, the point x=0 has maximum displacement in the positive y-direction. Next when this point has zero displacement, the slope of the string is π/20. Which of the following expressions represents the displacement of string as a function of x (in metres) and t (in seconds)?
- y=0.025cos(400πt−2πx)
- y=0.0125cos(400πt−4πx)
- y=0.025cos(400πt−4πx)
- y=0.0125cos(200πt−4πx)
Q. A non uniform string of mass 45 kg and length 1.5 m has a variable linear mass density given by μ=Kx, where x is the distance from one end of the string and K is a constant. Tension in the string is 15 N (uniform). Find the time (in seconds) required for a pulse generated at one end of the string to travel to the other end.
Q. A transverse wave is travelling on stretched string with velocity u. Tension in the string is T and mass density of string is r. Find the velocity of cart V such that waves seem stationary w.r.t cart.
- √Tr
- 2√Tr
- 3√Tr
- None of these
Q. The displacement wave in a string is y=(3 cm)sin6.28(0.5x−50t) where x is in centimeters and t in seconds. The wavelength and velocity of the wave is
- 2 cm, 100 cms−1
- 10 cm, 50 cm−1
- 20 cm, 2 ms−1
- 2 m, 100 ms−1
Q. A figure shows a snap photograph of a vibrating string at t=0. The particle P is observed moving up with velocity 20√3 cm/s. The tangent at P makes an angle 60∘ with x-axis. Then choose the correct option(s):
- Wave is moving along (+)ve x-axis.
- Wave is moving along (−)ve x-axis.
- Equation of wave is y=(0.4 cm) sin[(10πs−1)t+(π2cm−1x+π4].
- Equation of wave is y=(0.2 cm) sin[(10πs−1)t+(π2 cm−1)x−π2].
Q. A wave moves with speed 400 m/s on a wire , which is under a tension of 900 N. If the wave moves with 450 m/s, then the change in tension of the wire is
- +239 N
- −239 N
- +250 N
−250 N
Q. A figure shows a snap photograph of a vibrating string at t=0. The particle P is observed moving up with velocity 20√3 cm/s. The tangent at P makes an angle 60∘ with x-axis. Then choose the correct option(s):
- Wave is moving along (+)ve x-axis.
- Wave is moving along (−)ve x-axis.
- Equation of wave is y=(0.4 cm) sin[(10πs−1)t+(π2cm−1x+π4].
- Equation of wave is y=(0.2 cm) sin[(10πs−1)t+(π2 cm−1)x−π2].
Q. A wave travelling along a string is described by y(x, t)=0.008sin(85x−4t) in SI units, where x is in metres and t is in seconds . Calculate the wavelength and frequency of the wave.
- 8.4 cm, 1 Hz
- 14.8 cm, 0.64 Hz
- 7.4 cm, 1.28 Hz
- 7.4 cm, 0.64 Hz
Q. A wave travelling in the +ve x-direction having displacement along y-direction as 1 m, wavelength 2πm and frequency of 1πHz is represented by
- y=sin(x−2t)
- y=sin(2πx−2πt)
- y=sin(10πx−20πt)
- y=sin(2πx+2πt)
Q. The equation of a standing wave produced on a string fixed at both the ends is y=0.4sin(0.314x)cos(600πt), where x is in cm, t is in seconds. The smallest possible length of the string would be
- 20 cm
- 40 cm
- 10 cm
- None of these
Q. A string of length 60 cm fixed at both end is vibrating in its 2nd overtone. If mass per unit length of string is 0.2 kg/m, tension in string is 80 N and maximum amplitude of standing wave is 0.5 cm, then maximum speed of any point of string is
- 50π cm/s
- 40 cm/s
- 20π cm/s
- 60π cm/s
Q. Wave pulse on a string shown in figure is moving to the right without changing shape. Consider two particles at positions x1=1.5 m and x2=2.5 m. Their transverse velocities at the moment shown in figure are along directions.
- positive y-axis and positive y-axis, respectively
- negative y-axis and positive y-axis, respectively
- positive y-axis and negative y-axis, respectively
- negative y-axis and negative y-axis, respectively
Q. A 200 Hz sinusoidal wave is travelling in the positive x-direction along a string with a linear mass density of 4×10−3 kg/m and a tension of 40 N. At time t=0, the point x=0 has maximum displacement in the positive y-direction. Next when this point has zero displacement, the slope of the string is π20. Which of the following expressions respresent the displacement of string as a function of x (in metre) and t (in seconds).
- y=0.025cos(400πt+2πx)
- y=0.025cos(4πx−400πt)
- y=0.0125cos(4πx−400πt)
- y=0.0125cos(4πx+400πt)
Q. A wave travelling along a string is described by y(x, t)=0.008sin(85x−4t) in SI units, where x is in metres and t is in seconds . Calculate the wavelength and frequency of the wave.
- 8.4 cm, 1 Hz
- 14.8 cm, 0.64 Hz
- 7.4 cm, 1.28 Hz
- 7.4 cm, 0.64 Hz
Q. A 5.5m length string has a mass of 0.035kg. If the tension in the string is 77N. The speed of a transverse wave on the string is
- 110ms−1
- 165ms−1
- 102ms−1
- 77ms−1
Q. y - x curve at an instant for a wave travelling along x axis on a string is shown. Slope at the point A on the curve, as shown , is tan53∘
- Transverse velocity of the particle at point A is positive if the wave is travelling along positive x axis.
- Transverse velocity of the particle at point A is positive if the wave is travelling along negative x axis.
- Magnitude of transverse velocity of the particle at point A is greater than wave speed.
- Magnitude of transverse velocity of the particle at point A is lesser than wave speed.
Q. Two long strings A and B each having linear mass density 1.2×10−2 kg/m are stretched by different tensions 4.8 N and 7.5 N respectively and are kept parallel to each other with their left ends at x=0. Wave pulses are produced on the string at the left ends at t=0 on string A and t=20 ms on string B. When will the pulse on B overtake that on A for the first time?
- 0.1 s
- 0.4 s
- 0.5 s
- 0.25 s
Q. A transverse pulse generated at the bottom of a uniform rope of length L, travels in upward direction. The time taken by it to travel the full length of rope will be
- √L2g
- √Lg
- √4Lg
- √2Lg
Q. A metallic wire of 1 m length has a mass of 10×10−2 kg. If a tension of 100 N is applied to a wire, what is the speed of transverse wave?
- 31.6 ms−1
- 10 ms−1
- 0.1 ms−1
- 200 ms−1
Q. The electric field part of an electromagnetic wave in an medium is represented by Ex = 0,
Ey=2.5NCcos[(2π×106rads)t−(π×10−2radm)x]
Ez = 0. The wave is
Ey=2.5NCcos[(2π×106rads)t−(π×10−2radm)x]
Ez = 0. The wave is
Q. Two block of masses 40 kg and 20 kg are connected by a wire that has a linear mass density of 1 g/m. These blocks are being pulled across horizontal frictionless floor by horizontal force F that is applied to 20 kg block. A transverse wave travel on the wave between the blocks with a speed of 400 m/s (relative to the wire). The mass of the wire is negligible compared to the mass of the blocks The magnitude of F is
- 160 N
- 320 N
- 240 N
- 400 N
Q. Which of the following is not true for this progressive wave y=4sin2π(t0.02−x100) where y and x are in cm & t in sec. [CMPT 2003]
- Its amplitude is 4 cm
- Its wavelength is 100 cm
- Its frequency is 50 cycles/sec
- Its propagation velocity is 50×103 cm/sec
Q. The amplitude of a wave disturbance propagating in the positive x-directions is given by
y=11+x2 at time t=0 and by
y=1[1+(x−1)2] at t=2 seconds
where x and y are in metres. The shape of the wave disturbance does not change curing the propagation, then the velocity of the wave is
y=11+x2 at time t=0 and by
y=1[1+(x−1)2] at t=2 seconds
where x and y are in metres. The shape of the wave disturbance does not change curing the propagation, then the velocity of the wave is
- 0.5 ms−1
- 2.0 ms−1
- none of the above
- 1.0 ms−1
Q. The electric field of an electromagnetic wave traveling through a vacuum is given by equation E=E0sin(kx−t). The quantity that is independent of wavelength is?
- k
- kω
- k2
- k3
Q. The electric field associated with an e.m. wave in vacum is given by →E=^i40cos(kz−6×108t), where E, z and t are in volt/m, meter and seconds respectively.The value of wave vector k is:
- 6m−1
- 3m−1
- 2m−1
- 0.5m−1
Q. Find the displacement of a point on the string as a function of position and time.