Work Done on & by the Object
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An elevator of total mass (elevator + passenger) is moving up with a constant speed of . A frictional force of is opposing its motion. The minimum power delivered by the motor to the elevator is [Take ]
36 kW
4 kW
40 kW
-40 kW
- mg2t28
- 3mg2t28
- 0
- −mg2t28
- Zero J
- 200 J
- 500 J
- 100 J
The descending pulley shown in figure (10-E7) has a radius 20 cm and moment of inertia 0.20 kg-m2. The fixed pulley is light and the horizontal plane frictionless. Find the acceleration of the block if its mass is 1.0 kg.
- +34mgh
- −14mgh
- +54mgh
- +mgh
Take [g=10 m/s2]
- 30 J;120 J
- −240 J;60 J
- 120 J;30 J
- 240 J;−60 J
The work done by the force on the body when it reaches x=4 m and x=7 m is
- 21 J and 33 J respectively
- 21 J and 15 J respectively
- 42 J and 60 J respectively
- 42 J and 30 J respectively
- 294 J
- 315 J
- 588 J
- 197 J
A string of length L and mass M is lying on a horizontal table. A force F is applied at one of its ends. Tension in the string at a distance y from the end at which the force applied is:
F
F(L−Y)M
Zero
F(L−Y)L
- 0
- Mgl
- −Mgl
- It depends on how fast the man goes up.
- 1 J
- −1 J
- 2 J
- −2 J
- 21.2 J
- 23.2 J
- Zero
- 17.68 J
- -0.5 J
- -1.25J
- 1.25J
- 0.5J
- − 16 J
- −4.5 J
- 4 J
- −4 J
- Dot product
- Cross product
- Work done by force
- Torque by a force
Work done by the force in displacing the body from displacment zero to 6 m is given by
- 10 J
- zero
- 60 J
- 20 J
- ka
- ka
- ka
- −k2a
Calculate the total work done by tension force on the system for 1 m distance covered.
- 803 N
- −803 N
- Zero
- None
- 6√5 N
- 8√5 N
- 10√5 N
- 12√5 N
- 12 J
- 8 J
- 16 J
- 6 J
- Zero
- −220 J
- +220 J
- 110 J
- 952J
- Zero
- 803J
- 110 J
- 7 J
- 10 J
- Zero
- 5 J
A bead B of mass ‘m’ can travel without friction on a smooth horizontal wire xx’. The bead is connected to a block of identical mass by an ideal string passing over an ideal pulley. The system, as shown, is in vertical plane.
System is initially released from rest in the position shown. Initial acceleration of block A is:
zero
g23g7
4g7
- +150 J
- Zero
- None
- −150 J
- −75 J
- 60 J
- −60 J
- 75 J
- 1.5 N
- 2.5 N
- 3.5 N
- 4.5 N
- 300 J
- 420 J
- 720 J
- none of these
- F(πr)
- zero
- F(r√2)
- F(2r)