Applications of Colloids
Trending Questions
Starch dispersed in hot water is an example of
Emulsion
Hydrophobic sol
Lyophilic sol
Associated colloid
- It prevents emulsions from splitting or coagulating
- It increases the stability of emulsions
- An emulsifying agent forms an interfacial film between the dispersed phase and the dispersion medium
- An emulsifying agent is soluble in both the dispersion phase and the dispersion medium
Which is not colloidal [CPMT 1984; MP PET 1989, 91]
Chlorophyll
Egg
Ruby glass
Milk
Gold number is [MP PET/PMT 1988]
The number of mg of lyophilic colloid which should be added to 10 ml of ferric hydroxide sol so as to prevent its coagulation by the addition of 1 ml of 10% sodium chloride solution
- The number of mg of lyophilic colloid which should be added to 10 ml of standard gold sol so as to prevent its coagulation by the addition of 1 ml of 10%
The mg of gold salt to be added to a lyophilic colloid to coagulate it
The mg of an electrolyte required to coagulate a colloid
Alum is used to purify water since it acts as
Bactericide
De-odorant
Softener
Coagulant
Which of the following is most effective in coagulating a ferric hydroxide sol [MP PET 1993, 97; M
Which of the following electrolytes is most effective in the coagulation of gold solution [KCET 1996]
Alum is used to purify water since it acts as
Bactericide
De-odorant
Softener
Coagulant
- Formation of delta
- Cottrel precipitator
- Alloying
- Ideal gas equation
On adding FeCl3 solution into NaOH solution, a possitively charged colloidal sol is obtained when they are in
100 mL of 0.1 M FeCl3+100 mL of 0.1M NaOH
50 mL of 0.1 M FeCl3+200 mL of 0.1M NaOH
10 mL of 0.1 M FeCl3+50 mL of 0.1M NaOH
200 mL of 0.1 M FeCl3+800 mL of 0.1M NaOH
50 ml of 1M oxalic acid is shaken with 0.5 g of wood charcoal. The final concentration of the solution after adsorption is 0.5 M. Calculate the amount of oxalic acid adsorbed per gram charcoal.
1.575 g
0.05 g
3.15 g
None
- ΔG, ΔH and ΔS all are negative.
- ΔG and ΔS are negative but ΔH is positive.
- ΔG is negative but ΔH and ΔS are positive.
- ΔG and ΔH are negative but ΔS is positive.
On addition of 0.5 mL of solution of 10% NaCl to 20 mL of red gold sol in presence of 0.025 g of starch, the coagulation is just prevented. The gold number of starch is
0.025
0.1
2.5
1
50 ml of 1M oxalic acid is shaken with 0.5 g of wood charcoal. The final concentration of the solution after adsorption is 0.5 M. Calculate the amount of oxalic acid adsorbed per gram charcoal.
1.575 g
0.05 g
3.15 g
None
Which one of the following is not a surfactant
100 mL of 0.1 M FeCl3 + 100 mL of 0.1M NaOH
50 mL of 0.1 M FeCl3 + 200 mL of 0.1M NaOH
10 mL of 0.1 M FeCl3 + 50 mL of 0.1M NaOH
200 mL of 0.1 M FeCl3 + 800 mL of 0.1M NaOH
Which of the following electrolytes is most effective in the coagulation of gold solution [KCET 1996]
Ferric hydroxide sol is positively charged colloid. The coagulating power of
ions would be in the order
Which one is not a colloidal solution
Air
Smoke
Blood
Ink
Which impurities are removed by the following reagents:
(c) Potassium hydroxide solution
Freundlich isotherm will be better for modeling
Physical adsorption
Chemical adsorption
Adsorption of liq on solid
None
Which of the following can be a possible contact angle with water for a colloidal particle?
0∘
30∘
60∘
100∘
Which is not colloidal [CPMT 1984; MP PET 1989, 91]
Chlorophyll
Egg
Ruby glass
Milk
Purple of Cassius is
Colloidal solution of gold
Colloidal solution of Sulphur
Colloidal solution of platinum
Oxyacids of gold
- 10
- 1
- 0.1
- 0.01
Gold number of haemoglobin is 0.03. Hence 100 ml of gold sol will require haemoglobin in what quantity so that gold is not coagulated by 10ml 10% NaCl solution
0.03 mg
0.003 mg
0.3 mg
300 mg
On addition of 0.8 mL of solution of 10% NaCl to 30 mL of red gold sol in presence of 0.03 g of starch, the coagulation is just prevented. The gold number of starch is
0.09
0.4
0.0375
5