Aufbau Principle
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Explain Aufbau Principle with an example.
- (n + 1)s
- (n+2)p
- (n+1)d
- (n+2)s
Electrons in an orbital are filled according to which rule?
- Cu
- Cr
- N
- Both A and B
Rules | Statements |
A) Hund's rule of maximum multiplicity | P) No two electrons in an atom can have the same set of quantum numbers |
B) Aufbau principle | Q) Half-filled and completely filled orbitals have extra stability |
C) Pauli's exclusion principle | R) Pairing of electrons in the orbitals belonging to the same subshell does not take place until each orbital is singly occupied |
D) Hiesenberg's Uncertainity Principle | S) It is impossible to determine the exact position and exact momentum of a subatomic particle simultaneously |
T) In the ground state of atoms, orbitals are filled in the order of their increasing energies |
- A)−R), B)−T), C)−P), D)−S)
- A)−S), B)−T), C)−Q), D)−R)
- A)−R), B)−T), C)−S), D)−P)
- A)−S), B)−P), C)−T), D)−Q)
Statement - I: Cd is a transition element.
Statement - II: Cd and Cd2+ both have completely filled d− orbitals in their ground state.
Statement - I is true; Statement - II is true; Statement - II is correct explanation for Statement - I
Statement - I is true; Statement - II is true; Statement - II is NOT the correct explanation for Statement - I
Statement - I is true; Statement - II is false
Statement - I is false; Statement - II is true
How is the order of energy of atomic orbitals established?
- 1s22s22p6
- 1s22s22p1
- 1s22s22p5
- 1s22s22p4
- n=3, l=0
- n=3, l=0
- n=3, l=2
- n=4, l=0
- 3s 3p 3d 4s
- 3s 3p 4s 3d
- 3s 4s 3p 3d
- 4s 3s 3p 3d
Which one of the following configuration represents a noble gas
1s2, 2s2 2p6, 3s2
1s2, 2s2 2p6, 3s1
1s2, 2s2 2p6
1s2, 2s2 sp6, 3s2 3p6, 4s2
- 1s22s22p63s23p64s2
- 1s22s22p63s23p64s1
- 1s22s22p63s23p63d2
- 1s22s22p63s23p64s0
Which of the following orbital has most energy in multi-electron system?
3s
4p
4d
4s
- 4p < 3d < 4s
- 4s < 4p < 3d
- 4s < 3d < 4p
- 3d < 4s < 4p
- If Aufbau principle is not followed, then Sn (atomic number = 50) would be placed in d− block of the periodic table
- 5th ionization energy of As (Z=33) is less than that of Ge (Z=32)
- Increasing order of first ionization energy of S, Se and Cl is Se<S<Cl
- Ionic radii of Mg2+(Z=12) is smaller than F−(Z=9)
(i) n = 4, l = 1(ii) n = 4, l = 0(iii) n = 3, l = 2 and (iv) n = 3, l = 1
Can be placed in order of increasing energy, from lowest to highest as
(i) < (iii) < (ii) < (iv)
(ii) < (iv) < (i) < (iii)
(iv) < (ii) < (iii) < (i)
(iii) < (i) < (iv) < (ii)
- Ar
- Ti
- Sc3+
- V5+
The ratio of atomic numbers of two elements ‘ P’ and Q is 2:7. The energy of the fourth orbit of single-electron species of P is Calculate the difference in the number of electrons present in the valence and penultimate shells of Q.
2
4
3
1
(1) n = 1, l = 0, m = 0
(2) n = 2, l = 1, m = -1
(3) n = 2, l = 1, m = +1
(4) n = 3, l = 2, m = +1
(5) n = 3, l = 2, m = 0
- 4 and 5
- 1 and 2
- 2 and 3
- None of these
Statement 1: The first ionization energy of Be is greater than that of B.
Statement 2: 2p-orbital is lower in energy than 2s.
- Both the statements are CORRECT, and Statement II is the CORRECT explanation of Statement I
- Both the statements are CORRECT, and Statement II is not a CORRECT explanation of Statement I
- If Statement I is CORRECT, but Statement II is INCORRECT
- If Statement I is INCORRECT, but Statement II is CORRECT
(i) n = 4, l = 1(ii) n = 4, l = 0(iii) n = 3, l = 2 and (iv) n = 3, l = 1
Can be placed in order of increasing energy, from lowest to highest as
(i) < (iii) < (ii) < (iv)
(ii) < (iv) < (i) < (iii)
(iv) < (ii) < (iii) < (i)
(iii) < (i) < (iv) < (ii)
Ψ(3s)=19√3(1a0)32(6−6σ+σ2)e−σ2;where σ=2r.Z3a0
What is the maxium radial distance of node from nucleus?
- (3+√3)a0Z
- a0Z
- 32×(3+√3)a0Z
- 2a0Z