Bohrs Derivations
Trending Questions
Calculate the wavelength of and line in the Paschen series.
Calculate the energy associated with the first orbit of He⊕. What is the radius of orbit?
- 0.3026 nm
- 0.20645 nm
- 0.02645 nm
- 0.03026 nm
- Either 12.09 eV or 10.2 eV
- Either 2.55 eV or 10.2 eV
- Either 13.6 eV or 3.4 eV
- Either 3.4 eV or 0.85 eV
- −13.6 eV
- −3.40 eV
- −0.85 eV
Calculate the wavelength of the first line in the Balmer series of hydrogen spectrum.
486 nm
911.7 ˚A
656.5 nm
434 nm
The electron belongs to the angular momentum of an e−in a Bohr's orbit of H atom is 4.2178 × 10−34 Kg.m2.Sec−1.
K - shell
L - shell
N - shell
M - shell
- +13.6 eV
- -6.8 eV
- -3.4 eV
- +6.8 eV
If the radius of the second Bohr orbit of hydrogen atom is r2, the radius of the third Bohr orbit will be
49r2
4r2
94r2
9r2
Which of the following are true according to the postulates of Bohr's theory?
- When an atom gets the required energy from outside, it jumps from lower orbits to higher orbits and remains there forever.
- When an atom gets the required energy from outside, it jumps from the lower orbit to a higher orbit and remains there for very short intervals of time and returns back to a lower orbit, radiating energy.
- Angular momentum of an electron is proportional to n.
- Angular momentum of an electron is independent of n.
- v=n2h3Ke28π3m2
- v=n3h38Ke2π2m2
- v=n3h324Ke2π3m2
- v=n3h324Ke2π3m3
- 6
- 9
- 12
- 18
- +32x
- −38x
- +34x
- −34x
- 5 eV
- 4 eV
- 3 eV
- 2 eV
The radius of the second Bohr orbit for hydrogen atom is:
(Plank’s const. H = 6.6262 x10−34Js; mass of electron = 9.1091 x 10−31kg; charge of electron e = 1.60210 x 10−19C; permittivity of vaccum ϵ0=8.854185×10−12kg−1m−3A2)
- 1.65Å
- 4.76Å
- 0.529Å
- 212Å
In the following questions two Statement - 1 (Assertion) and Statement - 2 (Reason) are provided. Each question has 4 choices (a), (b), (c) and (d) for its answer, out of which ONLY ONE is correct. Mark your responses from the following options:
Statement - 1 : Electromagnetic radiation will be emitted for the transition 2Pz→2px.
Statement - 2 : No transition of electron takes place between 2Pz and 2Px orbitals.
Both Statement-1 and Statement - 2 are true and Statement - 2 is the correct explanation of Statement - 1
Both Statement - 1 and Statement - 2 are true and Statement - 2 is not the correct explanation of Statement - 1
Statement - 1 is true but Statement - 2 is false.
Statement - 1 is false but Statement - 2 is true.
- −13.6 eV
- −3.40 eV
- −0.85 eV
The circumference of the first Bohr orbit in H atom is 3.322 × 10−10 m. What is the velocity of the electron of this orbit?
- 2.19 × 106 m/s
4.19 × 106 m/s
3.57 × 106 m/s
6.00 × 106 m/s
The angular momentum of electron in ‘d‘ orbital is equal to :
0 ℏ
√6 ℏ
√2 ℏ
2√3 ℏ
- n=2
- n=3
- n=1
- n=4
- B+
- C+
- B
- C
- n = 4 to n = 2
- n = 1 to n = 4
- n = 4 to n = 3
- n = 3 to n = 4
- −13.6 eV
- −3.40 eV
- −1.51 eV
- −0.85 eV
- 2.06×1016
- 3.06×1016
- 1.06×1018
- 2.06×1017
Calculate the wavelength of the first line in the Balmer series of hydrogen spectrum.
486 nm
911.7 ˚A
656.5 nm
434 nm
If the radius of the second Bohr orbit of hydrogen atom is r2, the radius of the third Bohr orbit will be
49r2
4r2
94r2
9r2
- 8/27
- 32/27
- 27/32
- None of these
The wave length of first member of Balmer series of a hydrogen atom is nearly (The value of Rydberg constant is 1.08 × 107m−1)
4400A0
5500A0
6600A0
7700A0
The electron belongs to the angular momentum of an e−in a Bohr's orbit of H atom is 4.2178 × 10−34 Kg.m2.Sec−1.
K - shell
L - shell
N - shell
M - shell
The number of waves in the fourth Bohr orbit of hydrogen is
3
4
9
12
- 2.725×106 m−1
- 2.725×10−6 m−1
- 3.725×106 m−1
- 2.725×106 cm−1