Compressibility Factor
Trending Questions
Q. A container (volume V) has an ideal gas at 4 atm and 300 K. This is connected by a tube with another container of volume 2 V, which has a gas at 8 atm and 600 K. What will be final pressure of each container if the temperature is maintained - the container with volume V at 300 K and the 2V one at 600 K?
Q. Compressibility factor for CO2 at 400 K and 71.0 bar is 0.8697. Molar volume of CO2 under these conditions is:
- 0.40 L
- 2.24 L
- 22.4 L
- 19.5 L
Q. At 27∘C, hydrogen is leaked through a tiny hole into a vessel for 20 minutes. Another unknown gas at the same temperature and pressure leaked through the same hole for 20 minute. After the effusion of the gases the mixture exerts a pressure of 9 atm. The hydrogen content of the mixture is 0.7 mole. If the volume of the container is 3 L, what is the molecular mass of the unknown gas (in g)?
Q. The best vacuum attained so far in a laboratory is 10−10 mm of Hg. The number of molecules of gas remaining per cm3 at 20 ∘C in this vacuum is:
- 3.29×104 molecules
- 3.29×105 molecules
- 3.29×106 molecules
- 3.29×107 molecules
Q. There are 10 identical containers of volume V, each of them have an ideal gas at a same temperature T. The first container has a pressure of 1 atm, the second one has a pressure of 2 atm, the third has a pressure of 3 atm and so on. The tenth container has a pressure of 10 atm. If all the 10 containers are connected by thin tubes, then what will be the final pressure (in atm)?
Q.
The reciprocal of compressibility factor of a real gas in the critical state is ?
38
34
83
13
Q. The compressibility factors for 1 mole of real gases at low pressure, high pressure and that of gases of very low molar masses are Z1, Z2 and Z3. These are
- Z1=(1−aRTV), Z2= 1, Z3=(1+PbRT)
- Z1=(1−aRTV), Z2=(1+PbRT), Z3= 1
- Z1=(1+PbRT), Z2=(1−aRTV), Z3=(1+PbRT)
- Z1=(1−aRTV), Z2=(1+PbRT), Z3=(1+PbRT)
Q. At low pressures (For 1 mole), the van der Waals equation is written as [p+aV2]V=RT The compressibility factor is then equal to:
- (1−aRTV)
- (1−RTVa)
- (1+aRTV)
- (1+RTVa)
Q. An ideal gas obeying kinetic theory of gases can be liquefied if:
- Its pressure is more than Pc at a temperature less than Tc
- Its temperature is more than critical temperature Tc
- Its pressure is more than critical pressure Pc
- It cannot be liquefied at any value of P and T
Q. The ideal gas law, although convenient, has limitations. Most gases tend to deviate from ideal behaviour. For 1 mole of gas, plotting a curve of Z=PVRT v/s P gives us an idea of the deviation.
For curve C, find Z for 1 l of the gas at a pressure where b is negligible and a=4.225 atm l2 mol2
For curve C, find Z for 1 l of the gas at a pressure where b is negligible and a=4.225 atm l2 mol2
- 0.95
- 1.46
- 0.32
- 0.83
Q.
The compressibility factor of an ideal gas is –
Zero
1
12
None of the above
Q. For a van der Waal's gas Vc=3b, Pc=a27b2
Tc=8a27bR. Numerically the compressibility factor of a van der Waals gas at the critical points is:
Tc=8a27bR. Numerically the compressibility factor of a van der Waals gas at the critical points is:
- 0.375
- 1
- 0.952
- 0.567
Q. The sketch shows the plot of Z vs P for 1 mole of a hypothetical gas at three distinct
temperatures:
Boyle's temperature is the temperature at which a gas shows ideal behaviour over a
pressure range in the low pressure region. Boyle's temperature (Tb)=aRb. If a plot is
obtained at temperatures well below Boyle's temperature, then the curve will show a negative deviation in the low pressure region and a positive deviation in the high pressure
region.
Which of the following is correct?
temperatures:
Boyle's temperature is the temperature at which a gas shows ideal behaviour over a
pressure range in the low pressure region. Boyle's temperature (Tb)=aRb. If a plot is
obtained at temperatures well below Boyle's temperature, then the curve will show a negative deviation in the low pressure region and a positive deviation in the high pressure
region.
Which of the following is correct?
- ab<0.4 kcalmol−1
- 1 kcalmol−1<12<2 kcalmol−1
- ab<0.2 kcalmol−1
- ab=1 kcalmol−1
Q. The vapour density of a mixture of NO2 and N2O4 at 27∘C is 38.3. How many moles of NO2 will be present in 500 g of the mixture?
- 3.485 mol
- 8.125 mol
- 2.185 mol
- 1.825 mol
Q. The number of moles of oxygen in one litre of air containing 21% oxygen by volume under standard conditions is ′X′. What is the value of X ?
- 0.009
- 9
- 21
- 0.21
Q. The compressibility factor for H2 which behaves as a real gas is
- 1−aRTV
- 1+PbRT
- RTV1−a