Distinguishing Test of Terminal and Non Terminal Alkynes
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Q. A compound ′X′ having molecular formula C5H8, reacts with ammoniacal AgNO3 to give a white precipitate and reacts with excess of KMnO4 to give the acid, (CH3)2CH−COOH. Therefore, X is:
- CH2=CH−CH=CH−CH3
- CH3−CH2−C≡C−CH3
- (CH3)2CH−C≡CH
- (CH3)2C=C=CH2
Q. A unknown gas 'A' decolourises bromine in CCl4 and forms a precipitate with ammoniacal silver nitrate. The gas 'A' is:
- C2H2
- C2H4
- C2H6
- CH4
Q. Which of these will react with acetylene ?
- NaOH
- Ammoniacal AgNO3 solution
- NH3
- HCl
- All of these
Q. A four carbon alkyne having weakly acidic character is....
- 1-butyne
- 2-butyne
- 1, 2-dimethylbutyne
- None of the above
Q. 
The products of the above reaction are :
The products of the above reaction are :
- Only CH3CH2COOH
- None of the above
Q. An unknown compound (A) has a molecular formula C4H6. When (A) is treated with excess of Br2/CCl4 a new compound (B) with formula C4H6Br4 is formed. (A) forms a white ppt. with ammonical silver nitrate solution. The compound (A) is :
- But-1-yne
- But-2-yne
- But-1-ene
- But-2-ene
Q. ALindlar′s←−−−−−CatalystR−C≡C−RBirch reduction⟶B
Where, A and B are geometrical isomers (R−CH=CH−R).
Choose the correct option from the following:
Where, A and B are geometrical isomers (R−CH=CH−R).
Choose the correct option from the following:
- A is trans, B is cis
- A and B both are cis
- A and B both are trans
- A is cis, B is trans
Q. Which will undergo reaction with ammonical AgNO3?
- CH3−CH2−CH2−CH=CH−CH3
- CH3−CH=CH−C≡CH
- CH3−CH2−CH=CH−CH2−CH3
- CH2=CH−CH2−CH3
Q. Acetylene reacts with ammoniacal AgNO3 forming
- Silver acetylene
- Silver acetate
- Disilver acetylide.
- Silver mirror
Q. The distinguishing test for triple bond containing acidic hydrogen is
- [Cu(NH3)2]+OH−
- Br2 in CCl4
- Alkaline KMnO4
- AlCl3
Q. A hydrocarbon, 'X' (C3H4) decolourises Br2/CCl4 solution forming 'Y'. 'X' gave a red precipitate of a compound 'Z' with ammoniacal cuprous chloride.
X, Y, and Z respectively are:
X, Y, and Z respectively are:
- CH2=C=CH2, CH2Br−CBr2−CH2Br, CH3−C≡C−Cu+
- CH3−C≡CH, CH3−CBr2−CHBr2, CH3−C≡C−Cu+
- CH3−C≡CH, CH3−CBr=CHBr, Cu+CH−2−C≡CH
- CH2=C=CH2, CH2Br−CH=CHBr; CH3−C≡C−Cu+
Q. Identify a reagent from the following list which can easily distinguish between 1-butyne and 2-butyne.
- Br2, CCl4
- H2, Pd, BaSO4
- Dilute H2SO4, HgSO4
- [Ag(NH3)2]NO3
Q. An unknown compound (A) has a molecular formula C4H6. When (A) is treated with excess of Br2/CCl4 a new compound (B) with formula C4H6Br4 is formed. (A) forms a white ppt. with ammonical silver nitrate solution. The compound (A) is :
- But-1-yne
- But-2-yne
- But-1-ene
- But-2-ene
Q. Acetylene reacts with ammoniacal AgNO3 forming
- Silver acetylene
- Silver acetate
- Disilver acetylide.
- Silver mirror
Q. Which hydrocarbon will react with NaNH2 to form sodium salt?
- Benzene
- Ethane
- Ethene
- Acetylene
Q. A hydrocarbon, 'X' (C3H4) decolourises Br2/CCl4 solution forming 'Y'. 'X' gave a red precipitate of a compound 'Z' with ammoniacal cuprous chloride.
X, Y, and Z respectively are:
X, Y, and Z respectively are:
- CH2=C=CH2, CH2Br−CBr2−CH2Br, CH3−C≡C−Cu+
- CH3−C≡CH, CH3−CBr2−CHBr2, CH3−C≡C−Cu+
- CH3−C≡CH, CH3−CBr=CHBr, Cu+CH−2−C≡CH
- CH2=C=CH2, CH2Br−CH=CHBr; CH3−C≡C−Cu+
Q. ALindlar′s←−−−−−CatalystR−C≡C−RBirch reduction⟶B
Where, A and B are geometrical isomers (R−CH=CH−R).
Choose the correct option from the following:
Where, A and B are geometrical isomers (R−CH=CH−R).
Choose the correct option from the following:
- A is trans, B is cis
- A and B both are cis
- A and B both are trans
- A is cis, B is trans
Q. Sort the following carbocations according to their stability.
- −H3C+
- Primary
- Secondary
- Tertiary
Q. Which will undergo reaction with ammonical AgNO3?
- CH3−CH2−CH2−CH=CH−CH3
- CH3−CH=CH−C≡CH
- CH3−CH2−CH=CH−CH2−CH3
- CH2=CH−CH2−CH3
Q. A compound ′X′ having molecular formula C5H8, reacts with ammoniacal AgNO3 to give a white precipitate and reacts with excess of KMnO4 to give the acid, (CH3)2CH−COOH. Therefore, X is:
- CH2=CH−CH=CH−CH3
- CH3−CH2−C≡C−CH3
- (CH3)2CH−C≡CH
- (CH3)2C=C=CH2
Q. Which of the following compound on reaction with O3/H2O produces Butanoic acid and formic acid ?
- 1-Pentyne
- 2-Pentyne
- Hex-3-yne
- Hex-2-yne
