Electron Gain Enthalpy
Trending Questions
Why is the electronegativity of oxygen greater than that of carbon?
- Cl(g)+e−→Cl−(g)
- O−(g)+e−→O2−(g)
- O(g)+e−→O−(g)
- S(g)+e−→S−(g)
- F−
- O
- O2−
- Na+
- Electron affinity of Y is low and ionisation energy of X is high
- Electron affinity of Y is high and ionisation energy of X is low
- Both electron affinity of Y and ionisation energy of X is high
- Both electron affinity of Y and ionisation energy of X is low
The ionization energy of F− is 320 kJ/mole. The electron gain enthalpy of fluorine would be?
-320 kJ/mole
-160 kJ/mole
320 kJ/mole
160 kJ/mole
In which of the following processes is energy liberated?
Cl = Cl+ + e−
HCl =H+ + Cl−
Cl + e−= Cl−
O− + e− = O−2
- −320 kJ mol−1
- −160 kJ mol−1
- +320 kJ mol−1
- 160 kJ mol−1
F = −332, Cl = −349, Br = −324, I = −295.
The less negative value for F as compared to that of CI is due to:
- Strong electron-electron repulsion in the compact 2p- sub shell of F.
- Weak electron - electron repulsion in the bigger 3p- sub shell of Cl
- Smaller electronegativity value of F than Cl
- (A) and (B) both
- An element which has high electronegativity always has high electron gain enthalpy
- Electron gain enthalpy is the property of a bonded atom
- Electronegativity is the property of a bonded atom
- Both electronegativity and electron gain enthalpy are usually directly related to nuclear charge and inversely related to atomic size.
Which of the following represents correct order of increasing electron gain enthalpy with negative sign for the elements 0, S, F and Cl? [CBSE AIPMT 2010]
CI< F< O< S
O< S< F< CI
F< S< O< CI
S< O< CI< F
Cl(g)+e−→Cl−(g) is 58×10−10 J
Calculate the ΔegH− of Cl atom in eV atom−1.
- −0.036 eV atom−1
- −3.480 eV atom−1
- +0.038 eV atom−1
- −0.361 eV atom−1
- F→F−
- H→H−
- Cl→Cl−
- O→O2−
F = −332, Cl = −349, Br = −324, I = −295.
The less negative value for F as compared to that of CI is due to:
- Strong electron-electron repulsion in the compact 2p- sub shell of F.
- Weak electron - electron repulsion in the bigger 3p- sub shell of Cl
- Smaller electronegativity value of F than Cl
- (A) and (B) both
Cl(g)+e−→Cl−(g) is 58×10−10 J
Calculate the ΔegH− of Cl atom in eV atom−1.
- −0.036 eV atom−1
- −3.480 eV atom−1
- +0.038 eV atom−1
- −0.361 eV atom−1
Electron gain enthalpy depends on:
Atomic size
Number of neutrons
Atomic weight
Nuclear charge
- -78.13
- -326.6
- 326.6
- 78.13
- The elements having large negative values of electron gain enthalpy generally act as strong oxidising agents
- The elements having low values of ionisation enthalpy act as strong reducing agents
- The formation of S2−(g) from S(g) is an endothermic process
- All of these
- An element which has higher electronegativity always has a higher electron gain enthalpy
- Electron gain enthalpy is the property of an isolated atom
- Electronegativity is the property of a bonded atom
- Both electronegativity and electron gain enthalpy are usually directly related to nuclear charge and inversely related to atomic size
For the processes K+(g) I⟶ K(g) II⟶K−(g)
Energy is released in (I) and absorbed in (II)
Energy is absorbed in (I) and released in (II)
Energy is absorbed in both the processes
Energy is released in both the processes
- O > S > Se
- S > O > Se
- S > Se > O
- O > Se > S
If one electron has been removed from an atom, it becomes increasingly difficult to remove the second and subsequent electrons from the resulting positively charged ions on account of electrostatic attraction.
The numerical value of energy involved in the given process K→K− is less than that of which of the following processes?
K−→K
K→K+
Both (a) and (b)
None of these
O(g)+e−→O−(g), ΔH1
F(g)+e−→F−(g), ΔH2
Cl(g)+e−→Cl−(g), ΔH3
O−(g)+e−→O2−(g), ΔH4
The correct statement(s) is/are
- ΔH3 and ΔH2 both are negative
- ΔH1 and ΔH4 both are positive
- ΔH1, ΔH2 and ΔH3 are negative
- ΔH4 is negative