Enthalpy of Solution
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Q.
Calculate enthalpy change for the change 8S(g)→S8(g)′ given that
H2S2(g)→2H(g)+2S(g), ΔH=239.0 k cal mol−1H2S2(g)→2H(g)+S(g), ΔH=175.0 k cal mol−1
+ 512.0 k cal
- 512.0 k cal
508.0k cal
-508.0 k cal
Q. Given are the bond enthalpies: ϵN≡N=945 kJ mol−1, ϵH−H=436 kJ mol−1 and ϵ(N−H)=391 kJ mol−1. The enthalpy change of the reaction
N2(g)+3H2(g)→2NH3(g) is
N2(g)+3H2(g)→2NH3(g) is
- −93 kJ mol−1
- −89 kJ mol−1
- −105 kJ mol−1
- 105 kJ mol−1