Entropy for a Reversible Process
Trending Questions
Q. The equilibrium constant for the reaction given below is 2.0×10−7 at 300 K. Calculate the standard entropy change if △H∘=28.40 kJmol−1 for the reaction:
PCl5(g)⇌PCl3(g)+Cl2(g)
PCl5(g)⇌PCl3(g)+Cl2(g)
- −33.6 Jmol−1K−1
- 33.6 Jmol−1K−1
- −43.6 Jmol−1K−1
- 43.6 Jmol−1K−1
Q. 1 mole of an ideal gas at 25∘C is subjected to expand reversibly 10 times of its initial volume. Calculate the change in entropy of expansions.
- 25.15 J K−1 mol−1
- 30.15 J K−1 mol−1
- 19.15 J K−1 mol−1
- 29.15 J K−1 mol−1
Q. 1 mole of an ideal gas at 20 atm pressure and 15 L volume expands such that the final pressure becomes 10 atm and the final volume becomes 60 L. Calculate the change in entropy for the process.
(Cp.m=30 J mole−1 K−1, R=253J/mol K, ln 2 = 0.7, ln 3 = 1.1).
(Cp.m=30 J mole−1 K−1, R=253J/mol K, ln 2 = 0.7, ln 3 = 1.1).
- 80.2 JK−1 mole−1
- 15.17 JK−1 mol−1
- 120×102 JK−1 mol−1
- 26.83 JK−1 mol−1
Q. Acetic acid forms a dimer in the gas phase
The dimer is held together by two hydrogen bonds with a total strength of 66.5 kJ per mole of dimer. At 25oC, the equilibrium constant for the dimerisation is 1.3×103 (pressure in atm). What is magnitude △S0 for the reaction? Assume that △H does not vary with temperature.
The dimer is held together by two hydrogen bonds with a total strength of 66.5 kJ per mole of dimer. At 25oC, the equilibrium constant for the dimerisation is 1.3×103 (pressure in atm). What is magnitude △S0 for the reaction? Assume that △H does not vary with temperature.
Q. Acetic acid CH3COOH can form a dimer (CH3COOH)2 in the gas phase. The dimer is held together by two H - bonds with a total strength of 77.43 kJ per mol of dimer.
If at 27∘C, the equilibrium constant for the dimerization is 1.096×103, then calculate the magnitude of ΔS∘ (in kJ) for the reaction:
2CH3COOH(g)⇌(CH3COOH)2(g) (Round upto 2 digits after decimal and ln(1.096×103)≈7 and R=8.3 JK−1mol−1)
If at 27∘C, the equilibrium constant for the dimerization is 1.096×103, then calculate the magnitude of ΔS∘ (in kJ) for the reaction:
2CH3COOH(g)⇌(CH3COOH)2(g) (Round upto 2 digits after decimal and ln(1.096×103)≈7 and R=8.3 JK−1mol−1)
Q.
For the homogeneous gas phase equilibrium 4NH3(g)+5O2(g)⇔4NO(g)+6H2O(g) the units of equilibrium constant ′K′C are
mol L−1
L mol−1
mol2 L2
L2 mol−2
Q. Calculate the entropy(JK−1 mol−1) change for the following reversible process:
α−Tin ⇌ β−Tin at 13∘C
1 mol at 1 atm
ΔHtrans=2288J mol−1
α−Tin ⇌ β−Tin at 13∘C
1 mol at 1 atm
ΔHtrans=2288J mol−1
- 8
- 10
- 5
- \N
Q. A sample of an ideal gas is expanded to twice its original volume of 1m3 in a reversible process for which P=αv2 where α=5 atm/m6 . If Cv, m=20 Jmol−1K−1, determine the approximate molar change in entropy for the process.
- 4 Jmol−1 K−1
- 47.35 Jmol−1 K−1
- 40 Jmol−1 K−1
- 4 Jmol−1 K−1
Q.
For the homogeneous gas phase equilibrium 4NH3(g)+5O2(g)⇔4NO(g)+6H2O(g) the units of equilibrium constant ′K′C are
mol L−1
L mol−1
mol2 L2
L2 mol−2