Entropy of Phase Change
Trending Questions
Q.
When water is cooled to ice, its entropy
increases
decreases
remains the same
becomes zero
Q.
When water is cooled to ice, its entropy
increases
decreases
remains the same
becomes zero
Q. Calculate the change in entropy for fusion of 1 mole of ice. The melting point of ice is 273 K and molar enthalpy of fusion for ice = 6.0 kJ mole−1
- △Sf =21.97 JK−1 mol−1
- △Sf =21.87 JK−1 mol−1
- △Sf =21.78 JK−1 mol−1
- △Sf =21.79 JK−1 mol−1
Q. Predict in how many of the following processes entropy change of the system is positive .
(i) CaCO3(s)→CaO(s)+CO2(g)
(ii) N2(g)+3H2(g)→2NH3(g)
(iii) HCl(g)+NH3(g)→NH4Cl(s)
(iv) 2SO2(g)+O2(g)→2SO3(g)
(v) Cooling of N2(g) from 20oC to −50oC
(i) CaCO3(s)→CaO(s)+CO2(g)
(ii) N2(g)+3H2(g)→2NH3(g)
(iii) HCl(g)+NH3(g)→NH4Cl(s)
(iv) 2SO2(g)+O2(g)→2SO3(g)
(v) Cooling of N2(g) from 20oC to −50oC
- In all the processess
- 3
- 1
- 2
Q. At 373 K, steam and water are in equilibrium and △vapH=40.98 kJ mol−1. What will be entropy change for conversion of water into steam?
H2O(l)→H2O(g)
H2O(l)→H2O(g)
- 109.8 J K−1 mol−1
- 31 J K−1 mol−1
- 21.98 J K−1 mol−1
- 326 J K−1 mol−1
Q.
Calculate entropy change for vaporization of 1 mole of liquid water to steam at 100∘C if ΔHv=40.8 kJ mol−1.
ΔSv=107.38 JK−1 mol−1
ΔSv=109.48 JK−1 mol−1
ΔSv=109.38 JK−1 mol−1
ΔSv=107.38 JK−1 mol−1
Q. At 373 K, steam and water are in equilibrium and △vapH=40.98 kJ mol−1. What will be entropy change for conversion of water into steam?
H2O(l)→H2O(g)
H2O(l)→H2O(g)
- 109.8 J K−1 mol−1
- 31 J K−1 mol−1
- 21.98 J K−1 mol−1
- 326 J K−1 mol−1
Q. The enthalpy of vaporization of water at 100oC is 40.63 kJ mol−1. It's entropy change for the vaporization would be :
- 406.3 J K−1 mol−1
- 108.9 J K−1 mol−1
- 108.9 kJ K−1 mol−1
- 4063 kJ K−1 mol−1
Q. Predict in how many of the following processes entropy change of the system is positive .
(i) CaCO3(s)→CaO(s)+CO2(g)
(ii) N2(g)+3H2(g)→2NH3(g)
(iii) HCl(g)+NH3(g)→NH4Cl(s)
(iv) 2SO2(g)+O2(g)→2SO3(g)
(v) Cooling of N2(g) from 20oC to −50oC
(i) CaCO3(s)→CaO(s)+CO2(g)
(ii) N2(g)+3H2(g)→2NH3(g)
(iii) HCl(g)+NH3(g)→NH4Cl(s)
(iv) 2SO2(g)+O2(g)→2SO3(g)
(v) Cooling of N2(g) from 20oC to −50oC
- In all the processess
- 3
- 1
- 2
Q. The enthalpy of vaporisation of liquid diethyl ether (C2H5)2O is 26 kJ mol−1 at its boiling point 35 oC. Calculate △So for conversion of vapour to liquid (condensation) at 35 oC.
- −84.41 J K−1 mol−1
- +84.41 J K−1 mol−1
- −48.41 J K−1 mol−1
- +48.41 J K−1 mol−1
Q. The enthalpy of vaporization of water at 100oC is 40.63 kJ mol−1. It's entropy change for the vaporization would be :
- 406.3 J K−1 mol−1
- 108.9 J K−1 mol−1
- 108.9 kJ K−1 mol−1
- 4063 kJ K−1 mol−1