Faraday's First Law
Trending Questions
If gas is formed at the cathode, the volume of gas formed at the anode under identical conditions is?
One mole of in a flask decomposes to attain the equilibrium . At the equilibrium the mole fraction of is . then will be:
- True
- False
- 1
- 1.5
- 0.5
- 2
- 0 g
- 63.5 g
- 2.0 g
- 127.0 g
- 9.65×104 s
- 19.3×104 s
- 28.95×104 s
- 38.6×104 s
0.0696 liters
0.864 liters
1.68 liters
3.45 liters
Anode : H2+2OH−→2H2O+2e−
Cathode : O2+2H2O+4e−→4OH−
- 190.5 g of Cu
- 381 g of Cu
- 643.33 A
- 321.6 A
Pb+SO2−4→PbSO4+2e−(anode)
PbO2+4H++SO2−4+2e−→PbSO4+2H2O(cathode)
- 190
- 530
- 265
- 132.5
If current produced in fuel cell, use for the deposition of Cu2+ in 1 L, 2 M CuSO4(aq) solution for 241.25 sec using Pt electrode. The pH of solution after electrolysis is:
- 1
- 2
- 3
- 4
When aq. AgNO3 is electrolysed using Pt electrodes if 3.2 g of O2 is liberated at the anode, the amount Ag that will be deposited at the cathode in grams is (at wt. of Ag = 108)
32 g
1.6 g
4.32 g
43.2 g
- is the same
- is different
- is zero
In an electroplating experiment m g of silver is deposited, when 4 amperes
of current flows for 2 minutes. The amount (in gms) of silver deposited by 6
amperes of current flowing for 40 seconds will be
[MNR 1991]
4 m
m/2
m/4
2m
During the electrolysis of an electrolyte, the number of ions produced, is directly proportional to the
[AFMC 2002]
Time consumed
Electro chemical equivalent of electrolysis
Quantity of electricity passed
Mass of electrons
What is the mass of silver deposited on the passage of 2 A current during the electrolysis of silver?
Electrochemical equivalent of silver = 1.18×10−3 gm C−1
- 2.28×10−3 gm
- 2.36×10−3 gm
- 2×10−3 gm
- Cannot be determined
Al3++3e−→Al
(atomic mass of Al = 27)
- 9.65×103C
- 1.93×104C
- 9.65×104C
- 4.34×105C
In an electroplating experiment m g of silver is deposited, when 4 amperes
of current flows for 2 minutes. The amount (in gms) of silver deposited by 6
amperes of current flowing for 40 seconds will be
[MNR 1991]
4 m
m/2
m/4
2m
Anode : H2+2OH−→2H2O+2e−
Cathode : O2+2H2O+4e−→4OH−
- 190.5 g of Cu
- 381 g of Cu
- 643.33 A
- 321.6 A
- 0.20
- 0.10
- 0.15
- 0.05
Al3++3e−→Al
(atomic mass of Al = 27)
- 9.65×103C
- 1.93×104C
- 9.65×104C
- 4.34×105C