Filling Up Electrons in Field Split Orbitals
Trending Questions
Q. The correct order of the calculated spin-only magnetic moments of complexes (A) to (D) is
(A)Ni(CO)4
(B)[Ni(H2O)6]Cl2
(C)Na2[Ni(CN)4]
(D)PdCl2(PPh3)2
(A)Ni(CO)4
(B)[Ni(H2O)6]Cl2
(C)Na2[Ni(CN)4]
(D)PdCl2(PPh3)2
- (C)<(D)<(B)<(A)
- (A)≈(C)<(B)≈(D)
- (C)≈(D)<(B)<A)
- (A)≈(C)≈(D)<(B)
Q. Which of the following is a high spin complex?
- [Co(NH3)6]3+
- [Fe(CN)6]4−
- [Ni(CN)4]2−
- [FeF6]4−
Q. Crystal field splitting energy (CFSE) for the complex [Fe(CN)4]− is ____ , when Δ>P.
- −2.0
- Δ+P
- 2+P
- 0
Q. Which of the following has square planar geometry?
- [CoCl4]2−
- [FeCl4]2−
- [NiCl4]2−
- [PtCl4]2−
Q.
Which of these statements about [Co(CN)6]3− is true?
[Co(CN)6]3− has no unpaired electrons and will be in a low-spin configuration.
[Co(CN)6]3− has four unpaired electrons and will be in a low-spin configuration.
[Co(CN)6]3− has four unpaired electrons and will be in a high-spin configuration.
[Co(CN)6]3− has no unpaired electrons and will be in a high-spin configuration.