Graham's Law of Effusion
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- 2.5 mL
- 2.5 L
- 3.5 L
- 4 L
- Near the ammonia bottle
- Throughout the length of the tube
- At the centre of the tube
- Near the hydrogen chloride bottle
- (1:√14:√7)
- (√14:√7:1)
- (√7:1:√14)
- (1:√7:√14)
- 417.4
- 28.0
- 14.91
- 2.0
- 4:1
- 1:4
- 2:1
- 1:8
- C2H6
- C10H22
- C5H12
- C9H14
If methane and helium are allowed to diffuse out of a container under identical conditions of temperature and pressure, the ratio of rate of diffusion of methane to helium is:
4.0
1.0
2.0
0.5
- 0.38
- 2.65
- 1.14
- 0.88
(Given: Molecular mass of Xe = 131 u)
- C2H6
- C10H22
- C5H12
- C9H14
See the figure
The valves of X and Y are opened simultaneously.
The white fumes of NH4Cl will first form close to which of A, B and C?
A
B
C
A, B and C simultaneously
- 1:4
- 2:1
- 1:8
- 4:1
Helium gas at 1 atm and SO2 at 2 atm pressure, temperature being the same, are released seprately at the same moment into 1m long evacuated tubes of equal diameters. If helium reaches the other end of the tube in ts, what distance SO2 would traverse in the same time interval in the other tube ?
25 cm
50 cm
60 cm
75 cm
- Diprotium and dideuterium
- Carbon dioxide and ethane
- Dideuterium and helium
- Ethene and ethane
Two containers A and B have the same volume. Container 'A' contains 5 mole of oxygen gas. Container 'B' contains 3 moles of He gas and 2 mole of CH4 gas. Both the containers are separately kept in vaccum at the same temperature. Both the containers have very small orifices of the same area through which the gases leak out. The rate of diffusion of O2 is how many times the rate of diffusion of He and CH4 mixture.
√8.832
√732
32√8.832
√328.8
- 89.87
- 99.87
- 79.87
- 69.87
Equal volumes of two gases A and B diffuse through a porous pot in 20s and 10s, respectively .If the molar mass of A be 80gmol−1, Find the molar mass of B.
MB=30gmol−1
MB=26gmol−1
MB=20gmol−1
MB=32gmol−1
Define: Diffusion
- pH1>pH2≈pH3>pH4
- pH1<pH2<pH3<pH4
- pH1<pH2<pH3≈pH4
- pH1>pH2>pH3>pH4
- 0.682
- 0.534
- 0.466
- 0.595
- 8.65 times of SO3
- 2.65 times of CO
- 11 times of CO2
- 4 times of SO2
- 118.9 cm
- 81.1 cm
- 150.1 cm
- 108.9 cm
The value of d in cm (shown in the figure as estimated from Graham’s law, is
- 8
- 12
- 16
- 20
50 ml of hydrogen difuses out through a small hole from a vessel in 20 minutes.The time needed for 40 ml of oxygen to diffuse out is ___.
12 min
64 min
8 min
32 min
The rates of diffusion of SO2, CO2, PCl3 and SO3 are in the following order –
PCl3>SO3>SO2>CO2
CO2>SO2>PCl3>SO3
SO2>SO3>PCl3>CO2
CO2>SO2>SO3>PCl3
The rate of diffusion of Methane at certain temperature is 2 times that of gas X. The molecular mass of X is___.
64
32
4
8
(Given: Molecular mass of Xe = 131 u)
- (1:√14:√7)
- (√14:√7:1)
- (√7:1:√14)
- (1:√7:√14)
(where P and M are pressures and molecular weights of gases A and B respectively)
- (PAPB)(MAMB)12
- (MAMB)(PAPB)12
- (PAPB)(MBMA)12
- (MAMB)(PBPA)12
- 1:4
- 2:1
- 1:8
- 4:1