Heat of Reaction
Trending Questions
Q. The enthalpy of solution of BaCl2(s) and BaCl2.2H2O(s) are – 20.6 and 8.8 kJ mol−1 respectively, the enthalpy change for the hydration of BaCl2(s) is:
- 29.4 kJ
- – 11.8 kJ
- – 29.4 kJ
- + 11.8 kJ
Q.
In an endothermic reaction, the value of ΔH is always________
Q.
Is negative delta H exothermic?
Q. Calculate the enthalpy change (△H) of the following reaction
2C2H2(g)+5O2(g)→4CO2(g)+2H2O(g) given average bond enthalpies of various bonds, i.e., C−H, C≡C, O=O, C=O, O−H as 414, 814 499, 724 and 640 kJ mol−1 respectively.
2C2H2(g)+5O2(g)→4CO2(g)+2H2O(g) given average bond enthalpies of various bonds, i.e., C−H, C≡C, O=O, C=O, O−H as 414, 814 499, 724 and 640 kJ mol−1 respectively.
- −2600 kJ mol−1
- +2573 kJ mol−1
- −2573 kJ mol−1
- +2600 kJ mol−1
Q. Calculate resonance energy of N2O from the following data
Hence, △H∘(N2O)=82 kJmol−1
Assume structure NΘ=N⨁=O
BE of (N≡N) bond=950 kJmol−1
(N=N) bond=420 kJ mol−1
O=O) bond=500 kJmol−1
(O=N) bond=610 kJmol−1
Hence, △H∘(N2O)=82 kJmol−1
Assume structure NΘ=N⨁=O
BE of (N≡N) bond=950 kJmol−1
(N=N) bond=420 kJ mol−1
O=O) bond=500 kJmol−1
(O=N) bond=610 kJmol−1
- −170 kJmol−1
- −356 kJmol−1
- −88 kJmol−1
- −190 kJmol−1
Q.
Is positive or negative?
Q. Carbon tetrachloride (CCl4) is mixed in 390 g of benzene to make a solution for supporting an organic chemical reaction in which mole fraction of benzene is 0.91. Find the molality of the CCl4 solution.
- 4.44 m
- 4.25 m
- 2.67 m
- 1.26 m
Q. Calculate △Hor for the reaction CH2Cl2(g)→C(g)+2H(g)+2Cl(g).
The average bond enthalpies of C - H and C - Cl bonds are 414 kJmol−1 and 330 kJ mol−1.
The average bond enthalpies of C - H and C - Cl bonds are 414 kJmol−1 and 330 kJ mol−1.
- 1488 kJ mol−1
- 1468 kJ mol−1
- 1478 kJ mol−1
- 1498 kJ mol−1
Q. Given, H2S(g)→HS(g)+H(g);△Hrxn=379.6 kJmol−1
H2 (g)+S (s)→H2S (g);
△H∘fH2S=−21.1 kJmol−1
H2(g)→2H(g) ; ΔH=438 kJmol−1
ΔHsublimation of S = 280 kJmol−1
Thus, △H∘fHS is
H2 (g)+S (s)→H2S (g);
△H∘fH2S=−21.1 kJmol−1
H2(g)→2H(g) ; ΔH=438 kJmol−1
ΔHsublimation of S = 280 kJmol−1
Thus, △H∘fHS is
- 138.5 kJmol−1
- −138.5 kJmol−1
- −277.0 kJmol−1
- +139.5 kJmol−1
Q.
Which of the following properties is not a function of state?
concentration
internal energy
enthalpy
entropy
Q. Given:
⎡⎢ ⎢ ⎢ ⎢ ⎢⎣H2 (g)+12O2 (g)=H2O (g); ΔH=−241.8 kJC2H2 (g)+52O2 (g)=2CO2 (g)+H2O (g); ΔH=−1300kJ⎤⎥ ⎥ ⎥ ⎥ ⎥⎦
Equal volumes of C2H2 and H2 are combusted under identical conditions. The ratio of heats evolved in the two cases is
⎡⎢ ⎢ ⎢ ⎢ ⎢⎣H2 (g)+12O2 (g)=H2O (g); ΔH=−241.8 kJC2H2 (g)+52O2 (g)=2CO2 (g)+H2O (g); ΔH=−1300kJ⎤⎥ ⎥ ⎥ ⎥ ⎥⎦
Equal volumes of C2H2 and H2 are combusted under identical conditions. The ratio of heats evolved in the two cases is
- 5.37/1
- 1/5.37
- 1/1
- none of these
Q. Given that:
C(graphite)+ O2(g)→CO2(g), ΔH=x kJ mol−1
C(graphite)+ 12O2(g)→CO(g), ΔH=y kJ mol−1
CO(g)+ 12O2(g)→CO2(g), ΔH=z kJ mol−1
Based on the given thermochemical equations, find out which one of the following algebric relationships is correct?
C(graphite)+ O2(g)→CO2(g), ΔH=x kJ mol−1
C(graphite)+ 12O2(g)→CO(g), ΔH=y kJ mol−1
CO(g)+ 12O2(g)→CO2(g), ΔH=z kJ mol−1
Based on the given thermochemical equations, find out which one of the following algebric relationships is correct?
- z=x+2y
- z=x−y
- z=x+y
- 2z=x−y
Q. A solution of 200 mL of 1 M KOH is added to 200 mL of 1 M HCl and the mixture after attaining reaction equilibrium shows a rise in temperature by △T1. The experiment is repeated by using 50 mL of 1 M KOH and 50 mL 1 M HCl which at equilibrium shows a rise in temperature by △T2. Thus:
- △T1=△T2
- △T1=4×△T2
- △T1=2×△T2
- △T1>△T2
Q. Which equation do not represent enthalpy change of reaction which correspond to the standard enthalpy change of atomisation of chlorine?
- 12Cl2(g)→Cl(g)
- 12Cl2(l)→Cl(g)
- Cl2(g)→2Cl(g)
- Cl2(l)→2Cl(g)
Q. The following sequence of reaction occurs in commercial production of aqueous nitric acid. 4NH3(g)+5O2(g)→4NO(g)+6H2O(l) ΔH=−904 kJ ...(1) 2NO(g)+O2(g)→2NO2(g) ΔH=−112 kJ ...(2) 3NO2(g)+H2O(l)→2HNO3(aq)+NO(g) ΔH=−140 kJ ...(3)
Determine the magnitude of total heat (in kJ/mole) liberated at constant pressure for the production of exactly 1 mole of aqueous nitric acid by this process
Determine the magnitude of total heat (in kJ/mole) liberated at constant pressure for the production of exactly 1 mole of aqueous nitric acid by this process
Q. Calculate the heat evolved when 496 g of white phosphorus P4 burns in air according to equation
P4(s)+5O2(g)→P4O10(s) ΔH=−3013 kJ/mol
P4(s)+5O2(g)→P4O10(s) ΔH=−3013 kJ/mol
- 60226 kJ
- 12052 kJ
- 1252 kJ
- 3052 kJ
Q. The average Xe - F bond energy is 34 kcal/mol, first I.E. of Xe is 279 kcal/mol, electron affinity of F is 85 kcal/mol and bond dissociation energy of F2 is 38 kcal/mol. Then, the enthalpy change for the reaction XeF4→Xe++F−+F2+F will be
- 367 kcal/mol
- 425 kcal/mol
- 292 kcal/mol
- 392 kcal/mol
Q. Calculate the heat evolved when 248 g of white phosphorus P4 burns in air according to equation
P4(s)+5O2(g)→P4O10(s) ΔH=−3013 kJ/mole
P4(s)+5O2(g)→P4O10(s) ΔH=−3013 kJ/mole
- 4266 kJ
- 9026 kJ
- 3013 kJ
- 6026 kJ
Q. The polymerisation of propene to linear polypropene is represented by the reaction:
where n has a large integral value. The average enthalpies of bond dissociation for (C=C) and (C−C) at 298 K are +590 and +331 kJmol−1, respectively. The enthalpy of polymerisation is
−360 kJmol−1. Find the value of n.
where n has a large integral value. The average enthalpies of bond dissociation for (C=C) and (C−C) at 298 K are +590 and +331 kJmol−1, respectively. The enthalpy of polymerisation is
−360 kJmol−1. Find the value of n.
Q. Calculate △Hor for the reaction CH2Cl2(g)→C(g)+2H(g)+2Cl(g).
The average bond enthalpies of C - H and C - Cl bonds are 414 kJmol−1 and 330 kJ mol−1.
The average bond enthalpies of C - H and C - Cl bonds are 414 kJmol−1 and 330 kJ mol−1.
- 1488 kJ mol−1
- 1468 kJ mol−1
- 1478 kJ mol−1
- 1498 kJ mol−1
Q. What is value of △U (heat change at constant volume) for reversible isothermal evaporation of 90 g water at 100oC. Assuming water vapour behaves as an ideal gas and (△Hvap)water=540 cal g−1
- 9×103 kcal
- 6×103 kcal
- 4.49×103 cal
- none of these
Q. Given, C(graphites)+O2(g)→CO2(g)
Δr H∘=−393.5 kJ mol−1
H2(g)+12 O2(g)→H2O(l);
ΔrH∘=−285.8 kJ mol−2
CO2(g+2H2O(l)→CH4(g)+2O2(g)
ΔrH∘=+890.3 kJ mol−1
Based on the above thermochemical equations, the value of Δr H∘ at 298K for the reaction, C(graphite)+2H2(g)→CH4(g) will be
Δr H∘=−393.5 kJ mol−1
H2(g)+12 O2(g)→H2O(l);
ΔrH∘=−285.8 kJ mol−2
CO2(g+2H2O(l)→CH4(g)+2O2(g)
ΔrH∘=+890.3 kJ mol−1
Based on the above thermochemical equations, the value of Δr H∘ at 298K for the reaction, C(graphite)+2H2(g)→CH4(g) will be
- +78.8kJmol(−1)
- +144.0kJmol(−1)
- −74.8kJmol(−1)
- −144.0kJmol(−1)
Q. The heats of combustion of rhombic and monoclinic sulphur are 70960 and 71030 cal/mol respectively. Calculate the heat of conversion of rhombic to monoclinic sulphur
- 70960 cal
- 71030 cal
- - 70 cal
- 70 cal
Q. One mole of soda ash dissolves in water with evolution of 25 kJ of heat. Dissociation of 1 mol of the hydrate crystals in water resulted in the absorption of 67 kJ of heat. The heat released due to hydration of soda ash is
- −92 kJ
- +42 kJ
- −42 kJ
- −102 kJ
Q.
Consider the following data:
ΔfH0 (N2H4, l) = 50 kJ/mol
ΔfH0 (NH3, g) = −46k J/mol
B.E.(N−H) = 393 kJ/mol and B.E.(H−H) = 436 kJ/mol, also ΔvapH(N2H4, l) = 18 kJ/mol
The N- N bond energy in N2H4 is
226 kJ/mol
154 kJ/mol
190 kJ/mol
45.45 kJ/mol
Q. The increase in internal energy of 1 kg of water at 1000C when it is converted into steam at the same temperture and at 1 atm (100 kPa) will be:
(The density of water and steam are 1000kg/m3 and 0.6kg/m3 respectively. The latent heat of vapourisation of water is 2.25 106 J/kg.)
(The density of water and steam are 1000kg/m3 and 0.6kg/m3 respectively. The latent heat of vapourisation of water is 2.25 106 J/kg.)
- 2.08×106 J
- 4×107 J
- 3.27×108 J
- 5×109 J
Q. If heat of dissociation of CHCl2COOH is 0.7 kcal/mol, then △H for the reaction:
CHCl2COOH+KOH→CHCl2COOK+H2O
CHCl2COOH+KOH→CHCl2COOK+H2O
- - 13 kcal
- +13 kcal
- -14.4 kcal
- -13.7 kcal
Q. The specific heats of iodine vapour and solid are 0.031 and 0.055 cal K−1 g−1 respectively. If heat of sublimation of iodine is 24 cal g−1 at 200oC, find its value at 250∘C.
- 5.7 cal g−1
- 11.4 cal g−1
- 22.8 cal g−1
- 45.6 cal g−1
Q. For the combustion of 1 mol of liquid benzene at 25oC, the heat of reaction at constant pressure is given by, C6H6(l)+152O2(g)→6CO2(g)+3H2O(l); ΔH=−780980 cal.
What would be the heat of reaction at constant volume?
What would be the heat of reaction at constant volume?
- 750985 cal
- −700980 cal
- −880090 cal
- −780006 cal
Q. Methane is a commercial source of H2 through the reaction
(I) CH4(g)+12O2(g)→CO(g)+2H2(g)
Based on the following thermochemical equations (II to IV)
(II) CH4(g)+2O2(g)→CO2(g)+2H2O(g); △H=−800 kJ
(III) CH4(g)+CO2(g)→2CO(g)+2H2(g); △H=+235 kJ
(IV) CH4(g)+H2O(g)→CO(g)+3H2(g); △H=+204 kJ
△H of equation (I) is
(I) CH4(g)+12O2(g)→CO(g)+2H2(g)
Based on the following thermochemical equations (II to IV)
(II) CH4(g)+2O2(g)→CO2(g)+2H2O(g); △H=−800 kJ
(III) CH4(g)+CO2(g)→2CO(g)+2H2(g); △H=+235 kJ
(IV) CH4(g)+H2O(g)→CO(g)+3H2(g); △H=+204 kJ
△H of equation (I) is
- -35.75 kJ
- - 39.25 kJ
- - 25.75 kJ
- + 25.75 kJ