Henry's Law
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- 1/16th of the total pressure
- 1/9th of the total pressure
- 2/3rd of the total pressure
- 1/8th of the total pressure
A binary liquid solution is prepared by mixing n-heptane and ethanol. Which one of the following statements is correct regarding the behaviour of the solution ?
The solution is non-ideal, showing positive deviation form Raoult's Law
The solution is non-ideal, showing negative deviation from Raoult's Law
n-heptane shows positive deviation while ethanol shows negative deviation from Raoult's Law
The solution formed is an ideal solution
- 0.762 bar
- 0.755 bar
- 0.764 bar
- 0.772 bar
(Assume both the gases have same partial pressure)
- KH(CO2)=KH(O2)
- Cannot be predicted
- KH(CO2)>KH(O2)
- KH(CO2)<KH(O2)
Considering the above statement to be true, it illustrates the applicability of :
- Dalton's law of partial pressure
- Henry's Law
- First Law of thermodyanics
- Graham's Law of diffusion
(where KH is henry's law constant)
- KH1>KH2>KH3
- KH1<KH2<KH3
- KH1<KH2>KH3
- KH1=KH2=KH3
Statement I:
The tanks used by scuba divers are filled with air diluted with helium.
Statement II:
For scuba divers , increased pressure increases the solubility of atmospheric gases in blood, thus more N2 is dissolved in blood underwater at high pressure
- Both the statements are correct.
- Both the statements are incorrect.
- Statement I is correct whereas statement II is incorrect
- Statement I is incorrect whereas statement II is correct
- Chloroethane + bromoethane
- Ethanol + acetone
- Benzene + toluene
- Acetone + chloroform
- 8.28×10−7
- 0.01
- 0.99
- 1.72×10−7
Two non-reactive monoatomic ideal gases have their atomic masses in the ratio . The ratio of their partial pressure, when enclosed in a vessel kept at a constant temperature is . The ratio of their densities is
- % of O2 in air decreases in summer due to high temperature
- Atmospheric pressure decreases in summer leading to reduced solubility of gases in water
- Solubility of gases in water decreases as the temperature increases due to increased Henry’s constant
- Aquatic species feel skin burn due to increased temperature of the water.
- 2890.4
- 145.2
- 285
- 28.94
- Pressure of the gas should not be too high.
- Pressure of the gas should be high.
- Gas should not undergo any reaction with the solvent and dissociation or association in the solvent.
- Temperatuure of the gas should not be too low or high.
- When temperature of the gas is too low
- Gas undergoes endothermic reaction with the solvent.
- Gas should not undergo any association/dissociation with the solvent
- Gas undergoes exothermic reaction with the solvent.
A mixture of white bauxite powder and coke is heated in nitrogen gas very strongly . The products are
Al2O3 , C2N2
Al (NO3)3 , CO
AlN , CO, Si Vapour
Al2 (CO3)3, N2O
- 1:1
- 8:9
- 7:8
- 1:2
- Increase in pressure
- Decrease in pressure
- Coke reacts with gases in air
- None of the above
- True
- False
Assume that He (g) exerts a partial pressure of 0.5 bar
Take Henry's Law constant for He (g) at 298 K as 145 kBar
The Henry's law constant for the solubility of N2 gas in water at 298K is 1.0 x 105 atm. The mole fraction of N2 is 0.8. The number of moles of N2 from air dissolved in 10 moles of water at 298K and 5 atm pressure is
4 x 10-4
4 x 10-5
5 x 10-4
4 x 10-6
(Where p is the partial pressure of gas over the solution, KH is Henry’s law constant and χ is mole fraction of the gas in the solution.)
- p2×χ=KH
- χ=pKH
- p×χ2=KH
- None of the above
- 1:1
- 8:9
- 7:8
- 1:2