Introduction to Le Chatelier's Principle
Trending Questions
- Both for physical and chemical equilibrium
- Only for chemical equilibrium
- Only for physical equilibrium
- Neither for B nor for C
If CO2 escapes from the system
- pH will decreases
- Hydrogen ion concentration will decrease
- H2CO3 concentration will remain unchanged
- The forward reaction will be favoured
[R=0.082 Latmmol−1K−1 , Atomic mass of bromine = 80]
H2(g)+I2(g)⇌2HI(g)
Fe(s)+S(s)⇌FeS(s)
- N2(g)+3H2(g)⇌2NH3(g)
- N2(g)+O2(g)⇌2NO(g)
N2(g)+3H2(g)⇌2NH3(g)+heat
The equilibrium shifts in forward direction-
- By increasing the concentration of NH3(g)
- By decreasing the pressure
- By decreasing the concentrations of N2(g) and H2(g)
- By increasing pressure and decreasing temperature
4HCl (g) + O2 (g) ⇌ 2H2O (g) + 2Cl2 (g) ΔH° = -114 kJ
What shifts the equilibrium to the left?
removing steam
increasing the total gas pressure
decreasing volume of the container
raising the temperature
A hypothetical reaction : A(g)+B(g)⇌C(g)+D(g) occurs in a single step, the specific rate constant of forward reaction at TK is 2.0×10−3mol−1L s−1. When start is made with equimolar amounts of A and B, it is found that the concentration of A is twice that of C at equilibrium. The specific rate constant of the backward reaction is ?
5.0×10−4mol−1Ls−1
8.0×10−3mol−1Ls−1
1.5×102mol−1Ls−1
None of these
[Co(H2O)6]3+(aq)pink +4Cl−(aq) ⇋ [CoCl4]2−(aq)blue+ 6H2O(l)
- △ H> o for the reaction
- △ H< o for the reaction
- △ H= o for the reaction
- The sign of △ H canot be predicted on the basis of this information
- 8 times
- 16 times
- 64 times
- 4 times.
Which of the following activity can reduce the equilibrium concentration of CO to half?
- Increasing pressure twice
- Increasing the volume of reaction container to two times of its initial value
- Adding two moles of CO2 gas
- Adding two mole of helium gas at constant pressure
2ClF3(g)⇌Cl2(g)+3F2(g)
log Keq v/s 1T (where temperature is in K) curve is obtained as following
Which of the following change will increase the concentration of Cl2 in an equilibrium mixture of Cl2, F2 and ClF3:
- Addition of inert gas at constant pressure
- Increase in temperature at constant volume
- Addition of catalyst at equilibrium
- Removal of F2(g) at equilibrium
For the gas phase reaction C2H4+H2⇌C2H6, ΔH = -32.7kcal carried out in a vessel, the equilibrium concentration of C2H4 can be increased by -
increasing the temperature
Increasing concentration of H2
Decreasing temperature
Increasing pressure
If CO2 escapes from the system
- pH will decreases
- Hydrogen ion concentration will decrease
- H2CO3 concentration will remain unchanged
- The forward reaction will be favoured
A reversible reaction is in equilibrium. If a factor is changed which affects it,
then
The speed of forward and backward reaction increases
The speed of forward and backward reaction decreases
Only the speed of that reaction increases which nullifies the factor
causing increase of speed
No difference
- H2(g)+Cl2(g)⇌2HCl(g)
- 2CO(g)+O2(g)⇌2CO2(g)
- N2(g)+3H2(g)⇌2NH3(g)
- PCl5(g)⇌PCl3(g)+Cl2(g)
- Forward reaction is favoured
- Backward reaction is favoured
- No effect
- None of the above
- Increasing the temperature
- Removing Cl2
- Increasing the volume of the container
- Adding F2
[Co(H2O)6]3+(aq)pink +4Cl−(aq) ⇋ [CoCl4]2−(aq)blue+ 6H2O(l)
- △ H> o for the reaction
- △ H< o for the reaction
- △ H= o for the reaction
- The sign of △ H canot be predicted on the basis of this information
- Forward reaction is favoured
- Backward reaction is favoured
- No effect
- None of the above
has reached equilibrium. The reaction may be made to proceed forward by
- Adding more C
- Adding more D
- Decreasing the temperature
- Increasing the temperature
When a change is brought about in pressure, temperature or concentration of a reversible reation which has attained equilibrium, the equilibria tries to shift in such a direction which would neutralize the effect of change. This is known as
First law of thermodynamics
Le-chatelier's principle
Ostwald's rule
Hess's law of constant heat summation
- Reduces the dissociation of PCl5
- Increases the dissociation of PCl5
- Does not affect the degree of dissociation of PCl5
- Decrease in the formation of PCl3(g)
PCl5(g)⇌PCl3(g)+Cl2(g)
CO(g)+Cl2(g)⇌COCl2(g)
If some Ni(s) is introduced in the container forming Ni(CO)4(g) then at new equilibrium:
- PCl3 concentration will increase
- PCl3 concentration will decrease
- Cl2 concentration will remain same
- CO concentration will remain same
The solubility of a solute in water varies with temperature as given by :S=Ae−ΔHRT, ΔH being the enthalpy of solution. For a given solute, variation of In S with temperature is as shown in the figure. The solute is expected to be ?
CaO
CuSO4
MgSO4
CuSO4.5H2O
If CO2 escapes from the system
- pH will decreases
- Hydrogen ion concentration will decrease
- H2CO3 concentration will remain unchanged
- The forward reaction will be favoured
On adding more NH3, the above equilibrium shifts:
- In the forward direction
- In the backward direction
- The complex dissociation faster
- None of these
In the above reaction which is the essential condition for the higher production of NO ?
- High temperature
- High pressure
- Low temperature
- Low pressure
- Raising temperature
- Lowering temperature
- Keeping temperature constant
- Decreasing the concentration of M and N
2SO3 (g) ⇌ 2SO2 (g) + O2 (g) ΔH°= +198 kJ
At equilibrium temperature, what shifts the equilibrium to right?
removing sulphur trioxide
adding sulphur trioxide
decreasing the temperature
Fastening decomposition of SO3
- 0.073
- 0.147
- 0.05
- 0.026