Ion Electron Method
Trending Questions
Q. When the following redox reaction
Cl2+OH−→ClO−3+Cl−+H2O
is balanced by ion-electron method , what will be the coefficient of Cl2 and OH− respectively?
Cl2+OH−→ClO−3+Cl−+H2O
is balanced by ion-electron method , what will be the coefficient of Cl2 and OH− respectively?
- 3, 6
- 2, 4
- 1.2
- 5, 5
Q. For a given reaction
aA+bB⟶cC+dD
where a, b, c, d are the stoichiometric coefficients of A, B, C, D respectively.
Choose the correct statement(s):
aA+bB⟶cC+dD
where a, b, c, d are the stoichiometric coefficients of A, B, C, D respectively.
Choose the correct statement(s):
- Equivalents of A =Equivalents of B
- Equivalents of A =(ba)Equivalents of B
- Equivalents of C =Equivalents of D
- Equivalents of C =(dc)Equivalents of D
Q. Identify the correct balanced redox reaction by using ion-electron method:
BiO−3+Mn2+→Bi3++MnO−4+H2O
BiO−3+Mn2+→Bi3++MnO−4+H2O
- 5BiO−3+22H++Mn2+→5Bi3++7H2O+MnO−4
- 5BiO−3+14H++2Mn2+→5Bi3++7H2O+2MnO−4
- 2BiO−3+4H++Mn2+→2Bi3++2H2O+MnO−4
- 6BiO−3+12H++3Mn2+→6Bi3++6H2O+3MnO−4
Q. ClO2+SbO−2→ClO−2+Sb(OH)−6
The balanced form of the above reaction in basic medium using oxidation number method is:
The balanced form of the above reaction in basic medium using oxidation number method is:
- 2ClO2+SbO−2+2OH−→2ClO−2+Sb(OH)−6+2H2O
- ClO2+SbO−2+2H2O+OH−→ClO−2+Sb(OH)−6
- 2ClO2+SbO−2+2H2O+2OH−→2ClO−2+Sb(OH)−6
- 2ClO2+4SbO−2+2OH−→ClO−2+4Sb(OH)−6+3H2O
Q. Identify the correct balanced redox reaction by using ion-electron method:
BiO−3+Mn2+→Bi3++MnO−4+H2O
BiO−3+Mn2+→Bi3++MnO−4+H2O
- 5BiO−3+22H++Mn2+→5Bi3++7H2O+MnO−4
- 5BiO−3+14H++2Mn2+→5Bi3++7H2O+2MnO−4
- 2BiO−3+4H++Mn2+→2Bi3++2H2O+MnO−4
- 6BiO−3+12H++3Mn2+→6Bi3++6H2O+3MnO−4
Q. Balance the following equation by ion electron method:
Cr2O2−7+C2H4O+H+→2Cr3++C2H4O2+H2O
Cr2O2−7+C2H4O+H+→2Cr3++C2H4O2+H2O
- Cr2O2−7+3C2H4O+12H+→2Cr3++3C2H4O2+6H2O
- Cr2O2−7+3C2H4O+8H+→2Cr3++3C2H4O2+4H2O
- Cr2O2−7+3C2H4O+4H+→2Cr3++3C2H4O2+2H2O
- 2Cr2O2−7+3C2H4O+8H+→4Cr3++3C2H4O2+4H2O
Q.
In the following reaction,
xMn2O7⟶yMnO2+zO2 x, y, and z respectively are:
2, 4, 3
- 2, 3, 4
4, 3, 2
None of these
Q. Balance the following equation :
PbS+H2O2→PbSO4+H2O
PbS+H2O2→PbSO4+H2O
- 2PbS+4H2O2→2PbSO4+4H2O
- PbS+4H2O2→PbSO4+4H2O
- PbS+2H2O2→PbSO4+2H2O
- 2PbS+2H2O2→2PbSO4+4H2O
Q. What is the coefficient of oxalate ion in the balanced form of following reaction?
MnO−4+C2O2−4+H+⟶Mn2++CO2+H2O
MnO−4+C2O2−4+H+⟶Mn2++CO2+H2O
- 4
- 2
- 3
- 5
Q.
Which of the following occurs due to redox reaction?
Liberation of gas on reaction of metal with dilute acid.
Burning of ribbon in air.
Formation of Ferrous sulphide when iron is heated with sulphur.
Precipitation reaction.
Q. What would happen when a small quantity of H2O2 is added to a solution of FeSO4 ?
Q.
In the standardization of using . The equivalent weight of is:
Q. What volume of O2(g) measured at 1 atm and 273 K will be formed by the action of 100 ml of 0.5 N of KMnO4 on hydrogen peroxide in an acidic solution?
KMnO4+H2SO4+H2O2→K2SO4+MnSO4+O2+H2O
KMnO4+H2SO4+H2O2→K2SO4+MnSO4+O2+H2O
- 0.12 L
- 0.03 L
- 0.56 L
- 1.12 L
Q.
Assume the following reaction is carried out in acidic medium.
6e−+Cr2O72−⟶2Cr3++7H2O
How many H+ do we need to add to the LHS to balance the H atoms?
10
6
7
14
Q. In the following reaction :
H2O2(aq)+Cl2O7(aq)→ClO−2(aq)+O2(g)
Moles of OH− and H2O respectively present in a balanced equation in a basic medium are x and y. Calculate the value of x+y:
H2O2(aq)+Cl2O7(aq)→ClO−2(aq)+O2(g)
Moles of OH− and H2O respectively present in a balanced equation in a basic medium are x and y. Calculate the value of x+y:
Q. Identify the correct balanced redox reaction by using ion-electron method:
BiO−3+Mn2+→Bi3++MnO−4+H2O
BiO−3+Mn2+→Bi3++MnO−4+H2O
- 5BiO−3+22H++Mn2+→5Bi3++7H2O+MnO−4
- 5BiO−3+14H++2Mn2+→5Bi3++7H2O+2MnO−4
- 2BiO−3+4H++Mn2+→2Bi3++2H2O+MnO−4
- 6BiO−3+12H++3Mn2+→6Bi3++6H2O+3MnO−4
Q. Balance the following equation :
PbS+H2O2→PbSO4+H2O
PbS+H2O2→PbSO4+H2O
- 2PbS+4H2O2→2PbSO4+4H2O
- PbS+4H2O2→PbSO4+4H2O
- PbS+2H2O2→PbSO4+2H2O
- 2PbS+2H2O2→2PbSO4+4H2O
Q. Identify the correctly balanced redox reaction using ion-electron method.
FeSO4+KMnO4+H2SO4→Fe2(SO4)3+MnSO4+H2O+K2SO4
FeSO4+KMnO4+H2SO4→Fe2(SO4)3+MnSO4+H2O+K2SO4
- 10FeSO4+2KMnO4+8H2SO4→5Fe2(SO4)3+2MnSO4+8H2O+K2SO4
- 2FeSO4+10KMnO4+4H2SO4→2Fe2(SO4)3+5MnSO4+8H2O+10K2SO4
- 8FeSO4+10KMnO4+2H2SO4→5Fe2(SO4)3+4MnSO4+H2O+2K2SO4
- 10FeSO4+8KMnO4+2H2SO4→4Fe2(SO4)3+2MnSO4+5H2O+K2SO4
Q. Balance by Ion electon method, Cr2O−27+Fe+2→Cr+3+H2O (in acidic medium).
- Cr2O−27+2Fe+2+14H+→Cr+3+2Fe+3+7H2O
- Cr2O−27+Fe+2+2H+→2Cr+3+Fe+3+H2O
- Cr2O−27+3Fe+2+14H+→2Cr+3+3Fe+3+H2O
- Cr2O−27+6Fe+2+14H+→2Cr+3+6Fe+3+7H2O
Q.
Balance the equation
Q.
In the following reaction,
xMn2O7⟶yMnO2+zO2 x, y, and z respectively are:
2, 4, 3
- 2, 3, 4
4, 3, 2
None of these