Limitations of First Law
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Q. The heat of formation of C2H5OH(l) is −66 kcal mol−1. The heat of combustion of CH3OCH3 (g) is −348 kcal mol−1. △Hf for H2O and CO2 are −68 kcal mol−1 and −94 kcal mol−1 respectively.
Then, the △H for reaction C2H5OH(l)→CH3OCH3(g) is :
Then, the △H for reaction C2H5OH(l)→CH3OCH3(g) is :
- △H=18 kcal mol−1
- △H=22 kcal mol−1
- △H=26 kcal mol−1
- △H=30 kcal mol−1
Q.
Standard enthalpy of combustion of CH4 is −890 kJ mol−1 and standard enthalpy of vaporisation of water is 40.5 kJ mol−1. Calculate the enthalpy change for the reaction :
CH4(g)+2O2(g)→CO2(g)+2H2O(g)
−890 kJ mol−1
−809 kJ mol−1
809 kJ mol−1
−971 kJ mol−1
Q. O(g)+e−→O−(g) ΔH1
O−(g)+e−→O−2(g) ΔH2
O2(g)→O+2(g)+e− ΔH3
O(g)→O+(g)+e− ΔH4
H2(g)→H+2(g)+e− ΔH5
H(g)→H+(g)+e− ΔH6
O(g)+2e−→O−2 ΔH7
Which of the following option(s) is/are correct?
O−(g)+e−→O−2(g) ΔH2
O2(g)→O+2(g)+e− ΔH3
O(g)→O+(g)+e− ΔH4
H2(g)→H+2(g)+e− ΔH5
H(g)→H+(g)+e− ΔH6
O(g)+2e−→O−2 ΔH7
Which of the following option(s) is/are correct?
- |△H1|>|△H2|
- |△H4|>|△H3|
- |△H5|>|△H6|
- |△H7| is +ve
Q. The difference between heats of reaction at constant pressure and at constant volume for the reaction 2C6H6(l)+15 O2(g)→12CO2(g)+6H2O(l) at 25∘C at in kJ is
- –7.43
- + 3.72
- –3.72
- + 7.43