Liquefaction of Gases and Critical Constants
Trending Questions
Calculate the number of moles of gas present in the container of volume 10 L at 300 K. If the manometer containing glycerin shows 5 m difference in level as shown in the diagram. calculate your answers up to two decimal points.
(Given: dglycerin=2.72 g/mL; dmercury=13.6 g/mL Tale R=0.08 Latmmol−1K−1)
- 400 R41
- 150 R41
- 300 R41
- 41 R400
- It is the highest temperature at which liquid and vapour can
co-exist. - Beyond this temperature, a gas cannot be liquefied by compression.
- At this temperature, the surface tension of the system is zero.
- At this temperature, the gas and the liquid phases have different critical densities.
- 83
- 38
- 3
- 13
- O2
- SO2
- N2
- CO2
GasC. Temp (K)C. Pressure (atm)P5.12.2Q3313R12634S13540
Which of the gas/gases cannot be liquefied at a temperature of 100 K and a pressure of 50 atmospheres?
- S only
- P only
- R and S
- P and Q
- 4.09 g mL−1
- 4.14 g L−1
- 4.14 kg L−1
- 2.04 g L−1
Estimate the diameter of an Ar atom.
- 4.14 g L−1
- 4.14 kg L−1
- 2.04 g L−1
- 4.09 g mL−1
The critical temperature of ammonia and hydrogen are 405.5K and 33.2K respectively. Ammonia can be liquefied at room temperature just by compression of the gas at high pressure. Liquifaction of hydrogen , on the other hand, requires cooling as well as compression. (True/False)
True
False
The van der Waals' parameters for gases W, X, Y and Z are
Gasa(litre2−atom/mol2)b(litre/mol)W4.00.027X8.00.030Y6.00.032Z12.00.027
Which one of these gases has the highest critical temperature?
W
X
Y
Z
- Its temperature is more than critical temperature Tc
- Its pressure is more than critical pressure Pc
- Its pressure is more than Pc at a temperature less than Tc
- It cannot be liquefied at any value of P and T
- Liquid - vapor equilibrium exist
- Substance may change from liquid to gas phase
- Substance may change from gas to liquid phase
- All of the above
- It is the highest temperature at which liquid and vapour can
co-exist. - Beyond this temperature, a gas cannot be liquefied by compression.
- At this temperature, the surface tension of the system is zero.
- At this temperature, the gas and the liquid phases have different critical densities.
The temperature at which a real gas obeys the ideal gas law over an appreciable range of pressure is called:
Boyle point
Boyle temperature
Both a and b
Neither a nor b
GasC. Temp (K)C. Pressure (atm)P5.12.2Q3313R12634S13540
Which of the gas/gases cannot be liquefied at a temperature of 100 K and a pressure of 50 atmospheres?
- S only
- P only
- R and S
- P and Q
- At T=500 K, P=40 atm, the state will be liquid
- At T=300 K, P=50 atm, the state will be gas
- At T<300 K, P=20 atm, the state will be gas
- At 300 K<T<500 K, P>50 atm, the state will be liquid
The temperature to which a gas must be cooled before it can be liquefied by compression is called as___.
Boyle's temperature
Critical temperature
Liquefaction temperature
Inversion temperature
Consider the following statements. The Van der Walls parameters are given as:
Select the correct alternates.
A alone
A and B
A, B and C
B and C
CitiesMussorieBangaloreDelhiGoaP in (N/m2)1.01×1051.2×1051.02×1051.21×105
Consider the above data and mark the place at which liquid will boil first.
- Mussorie
- Bangalore
- Delhi
- Goa
- 4.09 g mL−1
- 4.14 g L−1
- 4.14 kg L−1
- 2.04 g L−1
Reason (R): Above critical temperature, the molecular speed is high and intermolecular attractions cannot hold the molecules together because they escape because of high speed.
- Both A and R are true and R is the correct expalanation of A.
- Both A and R are true but R is not the correct explanation of A.
- A is true but R is false.
- A is false but R is true.
Calculate the volume occupied by 16 gram O2 at 300 K and 8.31 Mpa if PcVRTc=38 and PrVrTr=2.21 ⟮:R=8.314 MpaK−mol⟯
124.31 lit
124.31 mL
248.62 mL
248.62 L
The critical temperature of a gas is that temperature:
Above which it cannot remain a gas
Above which it cannot be liquefied by pressure
At which it solidifies
At which the volume becomes 0
Reason: ‘a’ indirectly measures the magnitude of attractive forces between the molecules.
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- Both assertion and reason are false.
- Both assertion and reason are true and reason is the correct explanation of assertion.
- Assertion is true but reason is false.
- Both assertion and reason are true but reason is not the correct explanation of assertion.
- Vc3
- RTc8Pc
- 9RTcVc
- 3PcV2c
I - Slope of isotherm at critical point is maximum.
II - Larger the value of Tc, easier is the liquefaction of gas.
III - van der Waals' equation of state is applicable below critical temperature at all pressures.
- Only I
- I & II
- II & III
- Only II