Millikan's Oil Drop Experiment
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Q.
Magnitude-of-electric-charge-on-a-single-electron-is
Q. The value of e/m for cathode rays
- Varies as the atomic number of the element forming the cathode in the discharge tube changes
- remains constant irrespective of the nature of gas.
- varies as the atomic number of the gas in the discharge tube changes
- has the smallest value when the discharge tube is filled with hydrogen
Q. In a Millikan's oil drop experiment, the charge on an oil drop is calculated to be −6.4×10−19 C. The number of excess electrons on the drop is:
- 3.9
- 4
- 5
- 6
Q.
If eme = 1.758820 × 1011 C kg−1
The mass of an electron is
9.1094 × 10−31
9.1094 × 10−21
6.1094 × 10−31
6.1094 × 10−21
Q. In a Millikan's oil drop experiment, the charge on an oil drop is calculated to be −6.4×10−19 C. The number of excess electrons on the drop is:
- 3.9
- 4
- 5
- 6
Q. An oil drop has a charge of 6.4×10−19 C. Find out the number of electrons in the oil drop.
- 4
- 8
- 2
- 3
Q. Millikan's oil drop experiment was conducted to find:
- Mass of an electron
- Charge on an electron
- Mass of proton
- Charge of a proton
Q. In the oil drop experimant, charge on electron came out to be −1.6×10−19 C. From Thomson's experiment, e/m value for electron calculated was 1.758820×1011 C/kg. Find the mass of the electron.
(Given: e is the magnitude of charge on electron)
(Given: e is the magnitude of charge on electron)
- 1.67×10−27 kg
- 9.1×10−31 kg
- 9.1×10−28 kg
- 1.67×10−31 kg
Q. Millikan’s oil drop experiment was conducted to measure the value of the:
- e/m ratio
- Charge ‘e’ on an electron
- Mass of a proton
- Mass of an electron
Q. In Millikan’s oil drop experiment the forces acting on the oil drop when oil drop is moving are gravitaional force, electrostatic force and viscous drag.
Which force will stop acting on the oil drop if it's speed is reduced to zero
Which force will stop acting on the oil drop if it's speed is reduced to zero
- Gravitational Force
- Electrostatic Force
- Viscous Drag
- All of the above
Q. In Millikan’s oil drop experiment, the forces acting on a moving drop of oil are:
- Gravitational force and viscous drag
- Gravitational force, electrostatic force and viscous drag
- Electrostatic force and acceleration force
- None of the above
Q.
Assume that Millikan performed the oil drop experiment. In the oil drop experiment, the following charges(in arbitrary units) were found on a series of oil droplets.
The data obtained is as follows:
2 × 10−19 C
4 × 10−19 C
6 × 10−19 C
Calculate the magnitude of the charge on the electron.
1.6 × 10−19 C
4 × 10−15 C
2 × 10−19 C
2 × 10−15 C
Q. An oil drop has 7.99 × 10−19 C charge. The number of electrons that the oil drop has is
- 2
- 5
- 3
Q. As a result of Millikan's oil drop experiment, value of electronic charge was found to be approximately equal to:
- 1.6×10−19 C
- −1.6×10−19 C
- 3.2×10−19 C
- −3.2×10−19 C
Q. The value of e/m for cathode rays
- Varies as the atomic number of the element forming the cathode in the discharge tube changes
- remains constant irrespective of the nature of gas.
- varies as the atomic number of the gas in the discharge tube changes
- has the smallest value when the discharge tube is filled with hydrogen
Q. An oil drop has 7.99 × 10−19 C charge. The number of electrons that the oil drop has is
- 2
- 5
- 3
Q. Charge on a proton is 1.6×10−19 C and its mass is calculated to be equal to 1.67×10−27 kg. Then e/m for proton is:
(e:Charge ; m:Mass)
(e:Charge ; m:Mass)
- Less than e/m value for electron
- Equal to e/m value for electron
- Greater than e/m value for electron
- Equal to e/m value for neutron
Q. In Milikan's oil drop experiment, which of the following charges can exist on an oil drop?
Charge on electron e = −1.6×10−19 C
Charge on electron e = −1.6×10−19 C
- 2.8×10−19 C
- 3.2×10−19 C
- 8.0×10−19 C
- 11.2×10−19 C
Q.
If eme = 1.758820 × 1011 C kg−1
The mass of an electron is
