Mole Concept
Trending Questions
Q.
Balance the equation:
Q.
What is the molar mass of iron?
Q.
Balance the reaction: Phosphorus burns in Chlorine gas to form Phosphorus pentachloride.
Q. 250 mL of a sodium carbonate solution contains 2.65 g of Na2CO3. If 10 mL of this solution is diluted to 1 L, what is the concentration of the resultant solution?
(Molar mass of Na2CO3 = 106 g/mol)
(Molar mass of Na2CO3 = 106 g/mol)
- 0.001 M
- 0.01 M
- 0.1 M
- 10−4 M
Q. A carbon compound containing carbon and oxygen has approximate molar mass equal to 290. On analysis it is found to contain 50% by mass of each element. Therefore molecular formula of the compound is
- C12O9
- C4O3
- C3O4
- C9O12
Q. The total number of electrons in 1.6 g of CH4 to that in 1.8 g of H2O is:
- Double
- The same
- Triple
- One fourth
Q. The weight of 181.60 mL of a diatomic gas at 0 ∘C and 1 bar pressure is 1 g. The mass of one molecule (in g) of the gas is:
(NA is the Avogadro's constant)
(NA is the Avogadro's constant)
- 62.5NA
- 125NA
- 120NA
- 75.5NA
Q. 3.011×1023 molecules of a gas weigh 14 g. Calculate the molecular mass of the gas.
- 18 u
- 12 u
- 14 u
- 28 u
Q. The pressure of a 1:4 mixture by moles of dihydrogen and dioxygen enclosed in a vessel is one bar. What will be the partial pressure of dioxygen?
- 0.8×104 bar
- 0.008 N m−2
- 8×104 N m−2
- 0.08 bar
Q.
Differentiate between a balanced and a skeletal chemical equation.
Q.
The gram formula mass of ZnSO4 is
(Given molar mass of Zn in 65 g/mol)
Q. The density of a 30% by mass solution of acetic acid in water is 1.250 g/mL. Its molarity is:
- 6.25 M
- 1.25 M
- 2.5 M
- 12.5 M
Q. Phosphoric acid (H3PO4) is prepared in a two-step process.
P4+5O2→P4O10
P4O10+6H2O→4H3PO4
186 g of phosphorus is made to react with excess oxygen which forms P4O10 that has a 60 % yield. In the second reaction, 80% yield of H3PO4 is obtained. The mass of H3PO4 produced is:
(Molar mass of phosphorous = 31 g/mol)
P4+5O2→P4O10
P4O10+6H2O→4H3PO4
186 g of phosphorus is made to react with excess oxygen which forms P4O10 that has a 60 % yield. In the second reaction, 80% yield of H3PO4 is obtained. The mass of H3PO4 produced is:
(Molar mass of phosphorous = 31 g/mol)
- 282.24 g
- 149.95 g
- 125.47 g
- 564.48 g
Q.
A glass of Water contains Moles of Water. How many molecules of water are present ?
Q. Tetra phosphorus decaoxide combines with water to form phosphoric acid by the following unbalanced chemical equation:
P4O10+H2O→H3PO4
In order to form 105.0 g of phosphoric acid, how much tetraphosphorus decaoxide will you need?
P4O10+H2O→H3PO4
In order to form 105.0 g of phosphoric acid, how much tetraphosphorus decaoxide will you need?
- 262.6 g
- 138.1 g
- 75.97 g
- 72. 42 g
Q.
No. of moles of water in 488.6 g of BaCl2.2H2O are (molecular weight of BaCl2.2H2O = 244.33)
2 moles
4 moles
3 moles
5 moles
Q.
What is the relation between a mole and a molecule?
Q. Calculate the percentage yield of sodium sulphate when 32.18 g of sulphuric acid reacts with excess sodium hydroxide to produce 37.91 g of sodium sulphate.
H2SO4+2NaOH(aq)→2H2O(l)+Na2SO4(aq)
H2SO4+2NaOH(aq)→2H2O(l)+Na2SO4(aq)
- 91.37%
- 80.9%
- 78.13%
- 61.35%
Q. 2 g of butane is burnt with an excess of oxygen to form CO2. What is the approximate amount of CO2 formed?
- 3 g
- 1.5 g
- 6 g
- 2 g
Q. Find the number of O-atoms in 23 moles of NO2.
- 4.014×1023
- 4.014×1020
- 8.029×1023
- 8.029×1020
Q. Find the number of millimoles of CH4 in a sample containing 1.2044×1021 CH4 molecules.
- 2
- 0.002
- 20
- 0.02
Q. There are two samples of HCl having concentrations of 1 M and 0.25 M. Find amongst the given options, the combination of these samples needed to prepare a 0.75 M HCl solution assuming no extra water is used.
- 50 mL, 20 mL
- 50 mL, 35 mL
- 20 mL, 10 mL
- 100 mL, 60 mL
Q. Find the total number of oxygen atoms in 6×106 formula units of the complex [Co(H2O)6]Cl2.
- 6×106
- 3.6×107
- 1.8×107
- 4.2×107
Q. A Solution of palmitic acid in benzene contains 4.24 g of acid per litre. When this solution is dropped on a surface, benzene evaporates and palmitic acid forms a unimolecular film on the surface. If we wish to cover an area of 500 cm2 with a unimolecular film, what volume of solution (in litres) should be used? The area covered by one palmitic acid molecule may be taken as 0.21 nm2.
Molecular weight of palmitic acid = 256 gmol−1.
Molecular weight of palmitic acid = 256 gmol−1.
- 4.38×10−5
- 2.4×10−5
- 4×10−41
- 56×105
Q. When magnesium is placed in lead (II) sulphate solution, it reacts to form magnesium sulphate and lead. How much lead (II) sulphate would be required to react with 327 g of magnesium? (Molar mass of lead = 207 g/mol)
- 4128.4 g
- 1619.5 g
- 2788. 4 g
- 6868.4 g
Q. What volume of air at 1 atm and 273 K containing 21% of oxygen by volume is required to completely burn sulphur (S8) present in 200 g of sample, which contains 20% inert material which does not burn. Sulpur burns according to the reaction
18S8(s)+O2(g)→SO2(g)
18S8(s)+O2(g)→SO2(g)
- 23.52 L
- 320 L
- 112 L
- 533.33 L
Q. How much coulomb charge is present on 1g ion of N3−
Note: 1 mole of electrons have a charge of 96500 C.
Note: 1 mole of electrons have a charge of 96500 C.
- 5.2×106 Couloumb
- 2.894×105 Couloumb
- 6.6×106 Couloumb
- 8.2×106 Couloumb
Q.
The total weight of 1022 molecular units of CuSO4.5H2O is nearly
4.144 g
4.5 g
24.95 g
41.45 g
Q. A sample of ammonium phosphate (NH4)3PO4 contains 3.18 mol of hydrogen atoms. The number of moles of oxygen atoms in the sample is:
- 0.265 mol
- 0.795 mol
- 1.06 mol
- 4.00 mol
Q. One mole of oxygen gas at STP is equal to_____.
- 6.022×1023 molecules of oxygen
- 6.022×1023 atoms of oxygen
- 16 g of oxygen.
- 32 g of oxygen.