Ostwald Dilution Law
Trending Questions
Q. Calculate the H+ ion concentration of a 0.01 M weak monobasic acid. The value of dissociation constant is 4.0×10−10.
- 2×10−4mol L−1
- 2×10−8 mol L−1
- 2×10−2 mol L−1
- 2×10−6 mol L−1
Q. What will be the new pH if 0.01 mol of NaOH is added to a 1 L buffer solution that is 0.1 M in acetic acid (CH3COOH) and 0.1 M in sodium acetate (CH3COONa) ?
Dissociation constant Ka of acetic acid at 25∘C is 1.8×10−5
Dissociation constant Ka of acetic acid at 25∘C is 1.8×10−5
- 5.52
- 4.92
- 6.13
- 4.1
Q. The dissociation constant for a weak monobasic acid is 4×10−10. pH for this 0.01 N weak monobasic acid is :
- 9.7
- 1.7
- 3.7
- 5.7
Q.
The best indicator for titrating HCl with ammonium hydroxide is
litmus
phenolphthalein
methyl orange
phenol red
Q. Select the correct statement about Ostwald's dilution law :
- It is valid for weak electrolytes dissociation.
- It is useful in calculating ionisation constant of acids or bases.
- All of the above
- It is not valid for strong electrolytes.
Q. For a hypothetical reaction
4A + 5B⇋ 4P+6Q,
The equilibrium constant Kc has units
4A + 5B⇋ 4P+6Q,
The equilibrium constant Kc has units
- molL−1
- mol−1L
- (molL−1)−2
- unit less
Q. Select the correct statement about Ostwald's dilution law :
- It is valid for weak electrolytes dissociation.
- It is useful in calculating ionisation constant of acids or bases.
- It is not valid for strong electrolytes.
- All of the above
Q.
The equilibrium constant Kc for the reaction N2 (g) + 3H2 (g)⇋ 2NH3 (g) is:
[2NH3][N2][3H2]
[NH3][N2][3H2]3
[NH3]2[N2][3H2]
[NH3]2[N2][H2]3
Q. What will be the acidity of Magnesium hydroxide?
- 1
- \N
- 2
- 3
Q. Calculate pH of 1.0 M PO3−4 in aqueous solution. Given pKb of PO3−4=1.62.
- 13.19
- 7
- 6.5
- 11.5
Q.
Oswalds dilution law is applicable for both weak electrolytes and strong electrolytes- True or False?
True
False
Q.
If α is the degree of ionization, C the concentration of a weak electrolyte and Ka the acid ionization constant, then the correct relationship between α, Cand Ka is
α2 = √Ka × C.
α2 = √CKa
α = √KaC
α = √CKa