Oxidising and Reducing Nature

Q.

Why Lithium is the strongest-reducing agent?

Q. Why $PbC{l}_4$ exist but $Pb{I}_4$ doesn't ?

1. because $I^{-}$ get oxidised to $I_2$
2. because $I^{-}$ is a strong reducing agent
3. because $I_2$ is a gas
4. because $I^{-}$ is a strong oxidising agent

Q. Why $PbC{l}_4$ salt exist but $Pb{I}_4$ doesn't ?

1. because Iodine has electronegativity value
2. because $I^{-}$ is a strong reducing agent
3. because $I_2$ is a gas
4. because Iodine has large size

Q. Which of the following statements is incorrect ?

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1. $Na$ is used to make a $Na/Pb$ alloy
2. $MgS{O}_4$ is readily soluble in water
3. The oxidation state of $K$ in $K{O}_2$ is $+1$
4. $L{i}^{+}$ has minimum degree of hydration

Q. Which halide is least stable and has doubtful existence ?

1. $Ge{I}_4$
2. $Sn{I}_4$
3. $Pb{I}_4$
4. $C{I}_4$

Q.

Read the following and select one the correct answer.

Statement I: $P{b}^{4+}$ compounds are stronger oxidizing agents than $S{n}^{2+}$ compounds

Statement II: The higher oxidation states for the group 14 elements are more stable for the heavier members of the group due to inert pair effect.

1. Statement I and Statement II are both correct. Statement II correctly explains Statement I

2. Statement I and Statement II are both correct. Statement II does not explain Statement I

3. Statement II is correct and Statement I is wrong

4. Statement I is correct and Statement II is wrong

Q. It is because of the inability of $n{s}^2$ electrons of the valence shell to participate in bonding that:

1. $S{n}^{2+}$ is reducing while $P{b}^{4+}$ is oxidising
2. $S{n}^{2+}$ is oxidising while $P{b}^{4+}$ is reducing
3. $S{n}^{2+}$ and $P{b}^{2+}$ are both oxidising and reducing
4. $S{n}^{4+}$ is reducing and $P{b}^{4+}$ is oxidising

Q.

Of the following, the most stable hydride is

1. $Pb{H}_4$

2. $Sn{H}_4$

3. $Si{H}_4$

4. $C{H}_4$

Q. Element which act as a strong oxidising agent in its +4 oxidation state is

1. C
2. Sn
3. Pb
4. Si

Q. Which halide is least stable and has doubtful existence ?

1. $C{I}_4$
2. $Ge{I}_4$
3. $Sn{I}_4$
4. $Pb{I}_4$

Q. Given below are two statements :

Statement - I : $Ce{O}_2$ can be used for oxidation of aldehyde and ketones.

Statement - II : Aqueous solution of $EuS{O}_4$ is a strong reducing agent.

In the light of the above statements , choose the correct answer from the options given below :

JEE MAINS 2021

1. Statement I is true but Statement II is false
2. Both Statement I and Statement II are true
3. Statement I is false but Statement II is true
4. Both Statement I and Statement II are false

Q. The reducing power of divalent species decreases in the order

1. $G{e}^{2+}>S{n}^{2+}>P{b}^{2+}$
2. $S{n}^{2+}>G{e}^{2+}>P{b}^{2+}$
3. $P{b}^{2+}>S{n}^{2+}>G{e}^{2+}$
4. None of these

Q.

Carbon and silicon belong to (IV) group. The maximum coordination number of carbon in commonly occurring compounds is 4, whereas that of silicon is 6. This is due to

1. Large size of silicon

2. More electropositive nature of silicon

3. Availability of low lying d-orbitals in silicon

4. Both (a) and (b)