Reactions of Sulphuric Acid

Q. Hydrolysis of one mole of peroxy disulphuric acid produces:

1. Two moles of peroxy monosulphuric acid
2. Two moles of sulphuric acid
3. One mole of sulphuric acid and one mole of peroxy monosulphuric acid
4. Two moles of sulphuric acid and one mole of hydrogen peroxide

Q. Hydrolysis of one mole of peroxy disulphuric acid produces:

1. Two moles of peroxy monosulphuric acid
2. Two moles of sulphuric acid
3. One mole of sulphuric acid and one mole of peroxy monosulphuric acid
4. Two moles of sulphuric acid and one mole of hydrogen peroxide

Q.

Suppose, in your lab, you have run out of dilute Sulphuric acid. You require dilute $H_{2}S{O}_4$ for an important synthesis but only have concentrated Sulphuric acid, water and a glass beaker. How will you synthesize dilute $H_{2}S{O}_4$ ?

1. By adding water slowly to the concentrated $H_{2}S{O}_4$ taken in a glass beaker and stirring continuously

2. By adding concentrated $H_{2}S{O}_4$ to water taken in a beaker and stirring continuously

3. Both a and b

4. It is not feasible to prepare dilute dilute $H_{2}S{O}_4$ from concentrated $H_{2}S{O}_4$

Q. Hydrolysis of one mole of peroxy disulphuric acid produces:

1. Two moles of peroxy monosulphuric acid
2. Two moles of sulphuric acid
3. One mole of sulphuric acid and one mole of peroxy monosulphuric acid
4. Two moles of sulphuric acid and one mole of hydrogen peroxide

Q.

Suppose, in your lab, you have run out of dilute Sulphuric acid. You require dilute $H_{2}S{O}_4$ for an important synthesis but only have concentrated Sulphuric acid, water and a glass beaker. How will you synthesize dilute $H_{2}S{O}_4$ ?

1. By adding water slowly to the concentrated $H_{2}S{O}_4$ taken in a glass beaker and stirring continuously

2. By adding concentrated $H_{2}S{O}_4$ to water taken in a beaker and stirring continuously

3. Both a and b

4. It is not feasible to prepare dilute dilute $H_{2}S{O}_4$ from concentrated $H_{2}S{O}_4$