SHE
Trending Questions
Q. 8 L of H2 and 6 L Cl2 are allowed to react to their maximum possible extent. Find out the final volume of reaction mixture. Suppose P and T remains constant throughout the course of reaction.
- 2 L
- None of these
- 14 L
- 7 L
Q. Calculate the cell potential of the following cell at 25∘C.
Ag(s)|Ag+(aq, 0.001 M)||Ag+(aq, 0.5 M)|Ag(s)
Ag(s)|Ag+(aq, 0.001 M)||Ag+(aq, 0.5 M)|Ag(s)
- 0.03 V
- 0.159 V
- 1.09 V
- 0.52 V
Q.
Which of the following can be used to measure pH?
a glass electrode
concentration cell
a hydrogen electrode
all of these
Q. In the reaction:
2Al(s)+6HCl(aq)→2Al3+(aq)+6Cl−(aq)+3H2(g) Calculate the volume of H2 gas (L) produced at STP(atm) for every 3 mol of HCl consumed.
2Al(s)+6HCl(aq)→2Al3+(aq)+6Cl−(aq)+3H2(g) Calculate the volume of H2 gas (L) produced at STP(atm) for every 3 mol of HCl consumed.
- 33.6 L
- 44.8 L
- 67.2 L
- 22.4 L
Q. The value of Ereduction of a hydrogen electrode at pH=0 and 298 K, 1 atm is:
- 0.59 V
- 0 V
- −0.59 V
- −0.059 V
Q. Specific conductance of 0.1 M NaCl solution is 1.01×10−2ohm−1cm−1. Its molar conductance in ohm−1cm2mol−1 is :
- 1.01×102
- 1.01×104
- 1.01
- 1.01×103
Q. What is the reaction that takes place at the standard hydrogen electrode if it's coupled with metal-metal ion electrode of zinc (zinc in zinc sulphate solution).
- Pt→Pt++e−
- Pt++e−→Pt
- H2→2H++2e−
- 2H++2e−→H2
Q. For I2+2e−→2I−, standard reduction potential=+0.54 Volt.
For 2Br−→Br2+2e−, standard oxidation potential=−1.09 Volt.
For Fe→Fe2++2e−, standard oxidation potential=+0.44 Volt.
Out of the below given reactions, how many reactions are spontaneous in nature (predict from the above data) ?
Br2+2I−→2Br−+I2
Fe+Br2→Fe2++2Br−
Fe+I2→Fe2++2I−
I2+2Br−→2I−+Br2
For 2Br−→Br2+2e−, standard oxidation potential=−1.09 Volt.
For Fe→Fe2++2e−, standard oxidation potential=+0.44 Volt.
Out of the below given reactions, how many reactions are spontaneous in nature (predict from the above data) ?
Br2+2I−→2Br−+I2
Fe+Br2→Fe2++2Br−
Fe+I2→Fe2++2I−
I2+2Br−→2I−+Br2
Q. The standard hydrogen electrode has zero electrode potential because
- Hydrogen is easiest to oxidize
- The electrode potential is assumed to be 0 for the SHE
- Hydrogen has only one electron
- Hydrogen is lightest element
Q. Calculate the reduction potential for the following half cell at 25 oC.
Cu(s)|Cu2+(aq, 0.2 M); E0Cu/Cu2+=−0.34 V
Take :
[log10 5=0.7]
Cu(s)|Cu2+(aq, 0.2 M); E0Cu/Cu2+=−0.34 V
Take :
[log10 5=0.7]
Q. The value of Ereduction of a hydrogen electrode at pH=0 and 298 K, 1 atm is:
- 0.59 V
- 0 V
- −0.59 V
- −0.059 V