Solubility Product
Trending Questions
Q. Calculate the solubility of A2X3 in pure water, assuming that neither kind of ion reacts with water. The solubility product of A2X3, Ksp=1.1×10−23.
- 2.5×10−5 mol L−1
- 2.0×10−5 mol L−1
- 1.0×10−5 mol L−1
- 1.5×10−5 mol L−1
Q. What is the solubility of Al(OH)3, (Ksp=1×10−33) in a buffer solution having pH=4?
- 10−6 M
- 10−4 M
- 10−3 M
- 10−10 M
Q.
The Solubility s of AgCl(s) in pure water and in 0.1 M NaCl at 25∘C respectively are:
Ksp (AgCl) = 2.8 × 10−10
1.673 × 10−5 mol/litre in water, 1.4 × 10−9 mol/litre in 0.1 M NaCl
2.8 × 10−9 mol/litre in water, 1.673 × 10−5 mol/litre in 0.1 M NaCl
1.673 × 10−5 mol/litre in water, 2.8 × 10−9 mol/litre 0.1 M NaCl
1.732 × 10−9 mol/litre in water, 2.8 × 10−5 mol/litre 0.1 M NaCl
Q. Calculate the quantity of sodium carbonate (anhydrous) required to prepare 250 ml of 0.1 M solution:-
- 2.65 gm
- 4.95 gm
- 6.25 gm
- None
Q.
The solubility in water of a sparingly soluble salt AB2 is 1.0 × 10−5 mol l−1. Its
solubility product number will be
4 × 10−15
4 × 10−10
1 × 10−15
1 × 10−10
Q. What is the solubility of a sparignly soluble salt, PbSO4 in 0.01 M Na2SO4 solution ?
(Ksp for PbSO4=1.6×10−8)
(Ksp for PbSO4=1.6×10−8)
- 1.6×10−6mol L−1
- 2.6×10−9mol L−1
- 3.5×10−7mol L−1
- 0.4×10−9mol L−1
Q. Calculate pH of saturated solution of Mg(OH)2, Ksp for Mg(OH)2 is 32.0×10−12.
Given :log2=0.3010
Given :log2=0.3010
- 9.4
- 10.4
- 9.8
- 11.2
Q. The molar solubility of Cd(OH)2 is 1.84×10−5M in water. The expected solubility of Cd(OH)2 in a buffer solution of pH=12 is:
- 1.84×10−9M
- 2.49×10−M
- 6.23×10−11M
- 2.49×10−10M
Q. What is the minimum concentration of SO2−4 required to precipitate BaSO4 in a solution contining 1.0×10−4 mole of Ba2+? (Ksp for BaSO4=4×10−10)
- 4×10−10 M
- 2×10−7M
- 4×10−6M
- 2×10−3M
Q.
The solubility product of Mg(OH)2 at 25∘C is 1.4 × 10−11. The solubility of Mg(OH)2 in gm per litre is:
1.4 × 10−3
2.8 × 10−3
1.11 × 10−6
8.7 × 10−3
Q. One litre of saturated solution of CaCO3 is evaporated to dryness due to which 7.0 mg of residue is left. The solubility product for CaCO3 is:
- 4.9×10−5
- 4.9×109
- 4.9×10−9
- 4.9×10−7
Q. The pH of a solution obtained by mixing 100 mL of 0.2 M CH3COOH with 100 mL of 0.2 M NaOH will be: (pKa for CH3COOH=4.74)
- 4.74
- 9.1
- 8.87
- 8.87
Q. Ksp of M(OH)x is 27×10−12 and its solubility in water is 10−3 molL−1. The value of x is .
- 2
- 3
- 4