The Cannizaro Reaction

Q.

Using dilute sulphuric acid only how will you distinguish between:

Magnesium carbonate and magnesium sulphide.

Q. Which of the following compounds can give cannizzaro reaction?

1. 
2. 
3. 
4. All of these

Q. What is the name of the reaction when two moles of benzaldehyde got converted into benzyl alcohol and sodium benzoate in the presence of conc. NaOH?

1. Fridel - Craft's reaction
2. Kolbe's reaction
3. Wurtz reaction
4. Cannizzaro reaction

Q. An aldehyde which undergoes Cannizzaro’s reaction and reduces Schiff’s reagent but does not reduce Fehling’s solution is:

1. $C{H}_{3}CHO$
2. $HCHO$
3. $C_6{H}_{5}CHO$
4. salicylaldehyde

Q. In the Cannizzaro reaction given below:
$2Ph-CHO\stackrel{\stackrel{\ominus }{OH}}{\to }PH-C{H}_{2}OH+PhC{O}_2^{\ominus }$ the slowest step is:

1. The attack of $\stackrel{\ominus }{OH}$ at the carbonyl group
2. The transfer of hydride to the carbonyl group.
3. The abstraction of proton from the carboxylic acid.
4. The deprotonation of $Ph-C{H}_{2}OH.$

Q. How many cyclic esters will be formed in the following reaction?

Q. Consider following reaction sequence.


(D) has x number of double bond equivalents, the number of double bonds in (D) is y, the number of all stereoisomers of (D) is z. What is the value of x + y + z?

Q. Decarboxylation of cinnamic acid gives:

1. Benzene
2. Toluene
3. Styrene
4. Ethylbenzene

Q. $\underset{\left(A\right)}{(C{H}_3{)}_{3}C-CH=C{H}_2}\stackrel{HCl}{\to }B+C$
(Both of molecular formula $C_6{H}_{13}Cl$)

$B\underset{△}{\overset{alc.KOH}{\to }}D$ (an isomer of A)

$C\underset{△}{\overset{t-Bu-ONa}{\to }}A$

$D\underset{Zn}{\overset{O_3/H_{2}O}{\to }}E$
(This gives negative test with Fehling Solution but responds to iodoform test)

$A\underset{M{e}_{2}S}{\overset{O_3/H_{2}O}{\to }}F+G$
(Both give positive Tollens test but do not give iodoform test)

$F+G\stackrel{concNaOH}{\to }HCOONa+H$ (a primary alcohol)

$G\stackrel{concNaOH}{\to }H+J$

$H\underset{2.O_3/H_{2}O/Zn}{\overset{1.conc{H}_{2}S{O}_4/△}{\to }}E+K$

List-I contains questions related to reaction sequences given above and List-II contains their answers.

$\begin{array}{cc}\text{List - I}& \text{List - II}\\ \text{(I)Which compound(s) can perform cannizzaro}& \text{(P) K}\\ \text{reaction but not Aldol condensation reaction?}& \\ \text{(II) Which compound(s) when heated with conc}& \text{(Q) A}\\ H_{2}S{O}_4\text{give(s) mesitylene?}& \\ \text{(III) Which compound(s) performed rearrangement}& \text{(R) G}\\ \text{of 1, 2-methyl shift during reaction?}& \\ \text{(IV) Which compound(s) can perform Aldol}& \text{(S) H}\\ \text{condensation reaction but no Cannizzaro reaction}& \\ \text{when treated with dilute NaOH?}& \\ & \text{(T) E}\\ & \text{(U) F}\end{array}$

Which of the following options has the correct combination considering Lists-I and II?

1. $I\to P,U;II\to U$
2. $II\to S,T;IV\to P,Q$
3. $I\to R,U;III\to Q,S$
4. $III\to P,Q;II\to R,T$

Q. Benzyl alcohol and sodium benzoate is obtained by the action of sodium hydroxide on benzaldehyde. This reaction is known as

1. Perkin’s reaction

2. Cannizzaro’s reaction

3. Sandmeyer’s reaction
4. Claisen condensation

Q. A non C - C bond formation is not possible in :

1. Cannizaro reaction
2. Clenmenson reaction
3. Friedel crafts reaction
4. both (a) and (b)

Q. What is the final product 'P' in the following reaction sequence?

1. 
2. 
3. 
4. 

Q. A compound A with molecular formula $C_{10}{H}_{13}Cl$ gives a white precipitate on adding silver nitrate solution. A on reacting with alcoholic KOH gives compound B as the main product. B on ozonolysis gives C and D. C gives Cannizaro reaction but not alodol condensation. D gives aldol condensation but not Cannizaro reaction. A is:

1. 
2. $C_6{H}_5-C{H}_2-C{H}_2-\underset{\underset{Cl}{|}}{C}H-C{H}_3$
3. $C_6{H}_5-C{H}_2-C{H}_2-C{H}_2-C{H}_2-Cl$
4. 

Q. What is the final product 'P' in the following reaction sequence?

1. 
2. 
3. 
4. 

Q. The major product of the following reaction sequence is:

1. 
2. 
3. 
4.