VBT Tetrahedral vs Square Planar
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Q.
An aqueous solution of metal ion M1 reacts separately with reagents Q and R in excess to give tetrahedral and square planar complexes, respectively. An aqueous solution of another metal ion M2 always forms tetrahedral complexes with these reagents. Aqueous solution of M2 on reactionn with reagent S gives white precipitate which dissolves in excess of S. The reactions are summarised in the scheme given below:
SCHEME:
Reagent S is
K4[Fe(CN)6]
Na2HPO4
K2CrO4
KOH
Q.
Which of the following has net dipole moment?
BF3
CCl4
BeF2
SO2
Q. The structure of the complex [Pt(NH3)4]2+ is:
- Square planar
- Tetrahedral
- Pyramidal
- Pentagonal
Q. Both [Ni(CO)4] and [Ni(CN)4]2− are diamagnetic. The hybridisations of nickel in these complexes respectively are
- sp3, sp3
- sp3, dsp2
- dsp2, sp3
- dsp2, dsp2
Q. The correct energy level diagram for [Co(CN)6]3− is
Q. The ion which is not tetrahedral in shape is?
- BF−4
- NH+4
- [Cu(NH3)4]2+
- NiCl2−4
Q. The ion which is not tetrahedral in shape is?
- BF−4
- NH+4
- [Cu(NH3)4]2+
- NiCl2−4
Q. [Ni(CN)4]2⊖ and [NiCl4]2⊖ are dissimilar with respect to
- magnetic moment
- Coordination number
- structure
- Both (a) and (c)
Q. SF4, BF−4, ClF3, AsF3, PCl5, BrF5, XeF4, SF6
The number of species that have two lone pairs of electrons in their central atom is/are
(JEE (MAIN)-2021)
The number of species that have two lone pairs of electrons in their central atom is/are
(JEE (MAIN)-2021)