Van der Waal's Forces
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Q.
Which of the following gas has the largest value of a Van Der Waals Constant?
Q. Select the correct statements about van der Waals' constant ′b′
1. It is excluded volume
2. Its unit is mol L−1
3. It depends on intermolecular force
4. Its value depends on molecular size
1. It is excluded volume
2. Its unit is mol L−1
3. It depends on intermolecular force
4. Its value depends on molecular size
- 2, 3
- 1, 4
- 2, 3, 4
- 3, 4
Q. Arrange following in decreasing order of van der Waals' constant ′a′ values: H2O, CO2, Ar
- H2O>CO2>Ar
- Ar>H2O>CO2
- Ar=H2O>CO2
- H2O>Ar>CO2
Q. What is the compressibility factor (Z) for 0.02 mole of a van der waal's gas at pressure of 0.1 atm. Assume the size of gas molecule is negligible.
(Given: RT=20 L atm mol−1 and a=1000 atm L−2 mol−1)
(Given: RT=20 L atm mol−1 and a=1000 atm L−2 mol−1)
- 2
- 1
- 0.02
- 0.5
Q. van der Waals' constant 'b' of Ar is 3.22×10−5m3mol−1.Calculate the molecular diameter(in nm) of Ar.
Q. 4 g of argon (Atomic mass = 40) in a bulb at a temperature of T K has a pressure P atm. When the bulb was placed in a hot bath at a temperature 50∘C more that the first one, 0.8 g of the gas had to be removed to get the original pressure. T is equal to:
- 200 K
- 100 K
- 73 K
- 510 K
Q. Which of the following represents van der Waals gas below the critical temperature?
Q. The compressibility factor for a gas under critical conditions is:
- 83
- 1
- 14
- 38
Q. Statement–1: The value of the van der Waals constant ‘a’ is larger for NH3 than PH3.
Statement–2: Hydrogen bonding is present in NH3
Statement–2: Hydrogen bonding is present in NH3
- Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1
- Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1
- Statement-1 is True, Statement-2 is False
- Statement-1 is False, Statement-2 is True
Q. For a van der Waal's gas Vc=3b, Pc=a27b2
Tc=8a27bR. Numerically the compressibility factor of a van der Waals gas at the critical points is:
Tc=8a27bR. Numerically the compressibility factor of a van der Waals gas at the critical points is:
- 0.375
- 1
- 0.952
- 0.567
Q. a and b are van der Waals' constants for gases. Chlorine is more easily liquefied than ethane because
- Value of a for Cl2>C2H6
Value of b for Cl2<C2H6 - Value of a for Cl2<C2H6
Value of b for Cl2<C2H6 - Value of a for Cl2>C2H6
Value of b for Cl2>C2H6 - Value of a for Cl2<C2H6
Value of b for Cl2>C2H6
Q. The reduced temperature for benzene is 0.7277 and its reduced volume is 0.40. Calculate the reduced pressure of benzene.
- 40.358
- 30.358
- 20.358
- 10.358
Q. Select the correct statements about van der Waals' constant ′b′
1. It is excluded volume
2. Its unit is mol L−1
3. It depends on intermolecular force
4. Its value depends on molecular size
1. It is excluded volume
2. Its unit is mol L−1
3. It depends on intermolecular force
4. Its value depends on molecular size
- 2, 3
- 1, 4
- 2, 3, 4
- 3, 4
Q. In Vander Waal's equation of state for a non-ideal gas, the term that accounts for intermolecular forces is
- (V - b)
- (RT)−1
- RT
- (P+aV2)
Q. Calculate the pressure exerted by one mole of CO2 gas at 273 K if the van der Waal's constant, a=3.592 dm6 atm mol−2. Assume that the volume occupied by CO2 molecules is negligible.
- 0.9922 atm
- 1.9922 atm
- 9.9222 atm
- 0.1922 atm
Q. For compressibility factor, Z, which of the following is /are correct?
- For most of the real gases Z decreases with P at the lower pressure
- For most of the real gases Z increases with P at the higher pressure
- For H2 (g) and He(g) Z increases with P at all the pressure & at room temperature
- All of the above statements are correct
Q. Find the temperature (in K) at which 3 moles of SO2 will occupy a volume of 10 L at a pressure of 15 atm.
[ a=6.71 atm litre2 mol−2; b=0.0564 litre mol−1]
[ a=6.71 atm litre2 mol−2; b=0.0564 litre mol−1]
Q. Calculate the temperature of the gas (in kelvin) if it obeys van der Waals' equation from the following data. A flask of 2.5 L contains 10 mol of a gas under 50 atm. Given (a=5.46 atm L2 mol−2, b=0.031 L mol−1).
Q. Arrange following in decreasing order of van der Waals' constant ′a′ values: H2O, CO2, Ar
- H2O>CO2>Ar
- Ar>H2O>CO2
- Ar=H2O=CO2
- H2O>Ar>CO2
Q. At high pressure, van der Waals' equation becomes:
- PV=RT
- PV=RT+aV
- PV=RT−aV
- PV=RT+Pb