Work done in Isothermal Irreversible Process
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Q. Match the following
List IList IIA. Reversible isothermal expansion(p)w=−RPext[T2P1−T1P2]P1P2B. Irreversible isothermal expansion (q)w=Rγ−1[T2−T1]C. Reversible adiabatic expansion(r)w=−Pext(V2−V1)D. Irreversible adiabatic expansion(s)w=−nRT log(V2V1)
List IList IIA. Reversible isothermal expansion(p)w=−RPext[T2P1−T1P2]P1P2B. Irreversible isothermal expansion (q)w=Rγ−1[T2−T1]C. Reversible adiabatic expansion(r)w=−Pext(V2−V1)D. Irreversible adiabatic expansion(s)w=−nRT log(V2V1)
- A - (r), B - (s). C-(q), D - (p)
- A - (s), B - (r). C-(p), D - (q)
- A - (s), B - (r). C-(q), D - (p)
- A - (p), B - (r). C-(q), D - (s)
Q. 10 litres of a monoatomic ideal gas at 0oC and 10 atm pressure is suddenly exposed to 1 atm pressure and the gas expands adiabatically against this constant pressure to maximum possible volume. The final temperature and volume of the gas respectively are
- T = 174.8 K, V = 64 L
- T = 153 K, V = 57 L
- T = 165.4 K, V = 78.8 L
- T = 161.2 K, V = 68.3 L
Q. One mole of a gas is expanded from (1L, 10 atm, 300 K) to (4 L, 5 atm, 300 K) against a constant external pressure of 1 atm. The heat capacity of gas is 50 J/oC.Then the work done during the process is:
(Take 1Latm≃100J)
(Take 1Latm≃100J)
- −300 J
- −600 J
- 300 J
- −100 J
Q.
One mole of an ideal gas at 25∘C expands in volume from 1.0 L to 4.0 L at constant temperature. What work (in J) is done if the gas expands against vacuum ?
−4.0 × 102
−3.0 × 102
4.0 × 102 J
0 J
Q. Calculate the work done when 5 moles of oxygen gas contracts isothermally from 85 L to 15 L against a constant pressure of 2 atm at 250C.
- 70 L atm
- 14.0 L atm
- 140 L atm
- 7.0 L atm
Q. Match the following
List IList IIA. Reversible isothermal expansion(p)w=−RPext[T2P1−T1P2]P1P2B. Irreversible isothermal expansion (q)w=Rγ−1[T2−T1]C. Reversible adiabatic expansion(r)w=−Pext(V2−V1)D. Irreversible adiabatic expansion(s)w=−nRT log(V2V1)
List IList IIA. Reversible isothermal expansion(p)w=−RPext[T2P1−T1P2]P1P2B. Irreversible isothermal expansion (q)w=Rγ−1[T2−T1]C. Reversible adiabatic expansion(r)w=−Pext(V2−V1)D. Irreversible adiabatic expansion(s)w=−nRT log(V2V1)
- A - (r), B - (s). C-(q), D - (p)
- A - (s), B - (r). C-(p), D - (q)
- A - (s), B - (r). C-(q), D - (p)
- A - (p), B - (r). C-(q), D - (s)
Q. If a gas at 10 atm and 300 K expands against a constant external pressure of 2 atm from a volume of 10 litres to 20 litres, the amount of work done is:
Given: 1 L.atm = 101.3 J
Given: 1 L.atm = 101.3 J
- 17 L.atm
- 10 L.atm
- −2026 J
- 2026 J
Q. The reversible expansion of an ideal gas under adiabatic and isothermal conditions is shown in the figure. Which of the following statement(s) is/are correct?
- T1=T2
- T3>T1
- Wisothermal>Wadiabatic
- ΔUisothermal>ΔUadiabatic
Q. Find the work done when 5 moles of hydrogen contracts isothermally from 15 L to 5 L against a constant pressure of 1 atm at 250C.
- 685.3 cal
- −848.2 cal
- 422.5 cal
- −240.5 cal
Q. In a constant volume calorimeter, 3.5 g of a gas with molecular weight 28 was burnt in excess oxygen at 298.0 K. The temperature of the calorimeter was found to increase from 298.0 K to 298.45 K due to the combustion process. Given that the heat capacity of the calorimeter is 2.5kJK−1, find the numerical value for the enthalpy of combustion of the gas in kJmol−1.
- 9
- 5
- 3
- 2
Q. If a gas at 5 atm and 373 K expands against a constant external pressure of 1 atm from a volume of 2 litres to 10 litres, the amount of work done is:
(Given: 1L.atm=101.3 J)
(Given: 1L.atm=101.3 J)
- −402 J
- −525.3 J
- −212.8 J
- −810.4 J