Area between Two Curves
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Q.
Let the functions: and be defined by and . Then, the area of the region in the first quadrant bounded by the curves and is
Q. The graphs of f(x)=−x2+2 and g(x)=x3−x2−kx+2, k>0 are shown below. The graphs intersect and create two closed regions A and B.
Which of the following is (are) CORRECT?
Which of the following is (are) CORRECT?
- Area(A)=Area(B) ∀ k>0
- Area(A)=12Area(B) ∀ k>0
- Area(A)=4 sq. unit when k=4
- Area(B)=1 sq. unit when k=2
Q. The value of ∫202x3−6x2+9x−5x2−2x+5dx equals
- 4
- 1
- -1
- None of the above
Q. The area (in sq. units) of the region {(x, y)∈R2|4x2≤y≤8x+12} is :
- 1253
- 1283
- 1243
- 1273
Q. The area bounded by the curve f(x)=x+sinx and its inverse between the ordinates x=0 to x=2π is
- 4 sq. units
- 8 sq. units
- 4π sq. units
- 8π sq. units
Q. The region represented by |(x−y)|≤2 and |(x+y)|≤2 is bounded by a :
- rhombus of side length 2 units
- rhombus of area 8√2 sq.units
- square of side length 2√2 units
- square of area 16 sq. units
Q. The area of the region (x, y) : xy≤8, 1≤y≤x2 is
- 16log2e−143
- 8log2e−143
- 16log2e− 6
- 8log2e−73
Q. The area of the region above the x-axis, included between the parabola y2=ax and the circle x2+y2=2axis
- a2(π4−23) square units
- 2a2(π4−23) square units
- a(π4−23) square units
- a2(π4−23) square units
Q. ∫1−1e|x|dx
- e
- 2e
- e-1
- 0.02
Q.
Find the area enclosed between the curve y=5x−x2 and y=x .
16
32
323
329
Q. Suppose y=f(x) and y=g(x) are two functions whose graphs intersect at the three points (0, 4), (2, 2) and (4, 0). And also f(x)>g(x) for x∈(0, 2), f(x)<g(x) for x∈(2, 4). If 4∫0(f(x)−g(x))dx=10 and 4∫2(g(x)−f(x))dx=5, then the area between the two curves for x∈(0, 2) is
- 20
- 15
- 10
- 5
Q. The area of the region bounded by the curve y=tanx, the tangent to the curve at x=π4 and the x-axis is
- 14(loge4−1)
- 14(loge2−1)
- 12(loge4−1)
- 12(loge2−1)
Q. The area of the region described by A={(x, y):x2+y2≤1 and y2≤1−x} is :
- π2+43
- π2−43
- π2−23
- π2+23
Q. Let f(x)=x−x2 and g(x)=ax. If the area bounded by y=f(x) and y=g(x) is equal to the area bounded by the curves x=y−y2 and x+y=3, then the number of possible values of a is
Q. If Ai is the area bounded by |x−ai|+|y|=bi, i∈N, where ai+1=ai+32bi and bi+1=bi2, a1=0, b1=32, then
- A3=128
- A3=256
- limn→∞n∑i=1Ai=83(32)2
- limn→∞n∑i=1Ai=43(16)2
Q. The area (in sq. units) of the region bounded by the curve x2=4y and the straight line x=4y−2 is:
- 34
- 98
- 54
- 78
Q. The area bounded by the curve x=acos3t, y=asin3t is
- 3πa28
- 3πa216
- 3πa232
- 3πa2
Q. The area (in sq. units) bounded by the curve y=√x, 2y−x+3=0, x-axis, and lying in first quadrant is :
- 9
- 36
- 18
- 274
Q. The area (in sq. units) of the region bounded by the curves y=2x and y=|x+1|, in the first quadrant is :
- loge2+32
- 32−1loge2
- 12
- 32
Q. If the area (in sq. units) bounded by the parabola y2=4λx and the line y=λx, λ>0, is 19 , then λ is equal to :
- 4√3
- 2√6
- 24
- 48
Q. Let A(k) be the area bounded by the curves y=x2−3 and y=kx+2. Then
- the range of A(k) is [10√53, ∞)
- the range of A(k) is [20√53, ∞)
- If function k→A(k) is defined for k∈[−2, ∞), then A(k) is many- one function
- the value of k for which area is minimum is 1
Q. The area of the region inside the parabola 5x2−y=0 but outside the parabola 2x2−y+9=0 is
- 12√3 sq. units
- 6√3 sq. units
- 8√3 sq. units
- 4√3 sq. units
Q. The area (in sq. units) of the region {x∈R:x≥0, y≥0, y≥x−2 and y≤√x}, is :
- 133
- 83
- 103
- 53
Q. The area of the region
A={(x, y):0≤y≤x|x|+1 and −1≤x≤1} in sq. units, is :
A={(x, y):0≤y≤x|x|+1 and −1≤x≤1} in sq. units, is :
- 23
- 13
- 43
- 2
Q. The area of the region
A={(x, y):0≤y≤x|x|+1 and −1≤x≤1} in sq. units, is :
A={(x, y):0≤y≤x|x|+1 and −1≤x≤1} in sq. units, is :
- 23
- 13
- 43
- 2
Q. If the area (in sq. units) of the region {(x, y):y2≤4x, x+y≤1, x≥0, y≥0} is a√2+b, then a−b is equal to :
- 83
- 6
- 103
- −23
Q. Area bounded by y=|1−e|x|| and y=0 for x∈[−1, 1] is
- e−2
- e(e−2)
- 2(e−2)
- None of these
Q. The area bounded by y=x2, y=[x+1], x≤1 and the y-axis, where [.] represents the greatest integer function, is A sq. unit, then the value of 9A2 is
Q. The area bounded by y=x2, y=[x+1], x≤1 and the y-axis, where [.] represents the greatest integer function, is
- 23
- 13
- 73
- 1
Q. Let S(α)={(x, y):y2≤x, 0≤x≤α} and A(α) is area of the region S(α). If for a λ, 0<λ<4, A(λ):A(4)=2:5, then λ equals :
- 4(425)1/3
- 4(25)1/3
- 2(25)1/3
- 2(425)1/3