Binomial Expression
Trending Questions
Q. If Sn=n∑r=1r−1∑t=0(16n nCr rCt 4t), then the value of l, where l=∞∑n=1(1−Sn) is
Q. The coefficient of x7in the expansion of (1−x−x2+x3)6 is
- -132
- -144
- 132
- 144
Q. The set of values of x, which satisfy x2−13x+[x]+36=0 is
- [5, 7)
- (6, 7)
- [6, 7)
- (5, 7)
Q. If f(x+y, x−y)=xy, then f(x, y)+f(y, x)2 is
- x
- y
- 0
- x+y2
Q. The coefficient of x7in the expansion of (1−x−x2+x3)6 is
- -132
- -144
- 132
- 144
Q. If X={4n−3n−1:n∈N} and Y={9(n−1):n∈N}, where N is the set of natural numbers, then X∪Y is equal to:
- N
- Y−X
- X
- Y
Q. If n is a positive integer and Ck=nCk, then the value of n∑k=1k3(CkCk−1)2 is
- n(n+2)(n+1)212
- n(n+1)(n+2)212
- n(n+1)(n+2)12
- None of these
Q. Sum of the series nC1+2⋅5 nC2+3⋅52 nC3+⋯ upto n terms is
- n⋅6n−1
- 6n−1
- 6n
- n⋅6n
Q.
Find the sum of the series
∑r=0n(−1)r nCr[12r+3r22r+7r23r+15r24r⋯upto m terms]
2n−12mn(2n−1)
2m−12n(2n−1)
2mn−12mn(2n−1)
2mn−12mn(2m−1)
Q. S=n∑r=0(−1)r nCr[2r3r+8r32r+26r33r+...∞] is
- 3n3n−1
- 1
- 13n−1
- 23n−1
Q. Let a=(41/401−1) and for each n≥2, let bn= nC1+ nC2⋅a+ nC3⋅a2+ nCn⋅an−1. Then the value of b2020−b2019 is
- 42020/401
- 42019/401
- −42020/401
- −42019/401
Q. If (1+x)(1+x+x2).....(1+x+.....+xn)=a0+a1x+a2x2+a3x3+....., then the value of a0+a2+a4+..... is
- 2n−12
- 2n+12
- (n−1)!2
- (n+1)!2
Q. The given expression is (x+√x3−1)5+(x−√x3−1)5 is a
- polynomial of fractional degree.
- polynomial of degree 7.
- polynomial with integer degree.
- not a polynomial.
Q. If the coefficents of x3 and x4 in the expansion of (1+ax+bx2)(1−2x)18 in powers of x are both zero, then (a, b) is equal to:
- (14, 2723)
- (16, 2723)
- (16, 2513)
- (14, 2513)