Binomial Theorem
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Q.
If the coefficients of pth, (p+1)th and (p+2)th terms in the expansion of (1+x)n are in A.P., then
n2−n(4p+1)+4p2−2 = 0
n2−2np+4p2 = 0
n2−n(4p+1)+4p2 = 0
None of these
Q.
Verify that for all n≥1 , the sum of the squares of the first 2n positive integers is given by the formula 12+22+32+.....(2n)2=n(2n+1)(4n+1)3
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Q.
The value of (√2+1)6 + (√2−1)6 will be
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Q. The total number of solutions of [x]2=x+2(x}, where [.] and {.} denote the greatest integer function and the fractional part function, respectively, is equal to
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