Bisectors of Angle between Two Lines
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Equation of a straight line passing through the point (4, 5) and equally inclined to the lines 3x=4y+7 and 5y=12x+6 is
9x−7y=1
9x+7y=71
7x+9y=73
7x−9y+17=0
- 2 sq. units
- 4 sq. units
- 6sq. units
- 8 sq. units
The equation of the bisectors of the angles between the lines represented by x2+2xycotθ+y2=0, is
x2−y2 = 0
x2−y2 = xy
(x2−y2)cotθ = 2xy
- x2−y2 = 3xy
- 6x−2y−5=0
- 2x+6y−19=0
- 6x+2y−5=0
- 2x+6y+19=0
- BC:7x−3y+4=0
- BC:7x+3y+4=0
- B≡(5/2, 9/2)
- B≡(−5/2, 9/2)
- 3x + 11y - 4 = 0
- 99x - 27y – 2 = 0
- 3x + 11y + 4 = 0
- 99x + 27y - 2 = 0
If L1 and L2 be the angle bisectors of two lines, then the angle between L1 and L2 is90∘ .
True
False
The equation of the bisectors of the angles between the lines represented by x2+2xycotθ+y2=0, is
x2−y2 = 0
x2−y2 = xy
(x2−y2)cotθ = 2xy
- x2−y2 = 3xy
STATEMENT-1 : The ratio PR:RQ equals 2√2:√5.
because
STATEMENT-2: In any triangle, bisector of an angle divides the triangle into two similar triangles.
- Statement- 1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1
- Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1
- Statement-1 is True, Statement -2 is False
- Statement-1 is False, Statement-2 is True.
Find the value of for which the following system of linear equations has infinite solutions
- x-7y+2=0
- 7x+y-2=0
- 2y-7x-5=0
- 2x+7y+5=0
- 21x+27y+131=0
- 99x−77x−51=0
- 99x−77x+51=0
- 21x+27y−131=0
If L1 and L2 be the angle bisectors of two lines, then the angle between L1 and L2 is90∘ .
True
False
Equation of a straight line passing through the point (4, 5) and equally inclined to the lines 3x=4y+7 and 5y=12x+6 is
9x−7y=1
9x+7y=71
7x+9y=73
7x−9y+17=0
- 7
- −7
- 17
- −17
- the equation of line BC is 7x−3y+4=0
- the equation of line BC is 7x+3y+4=0
- B≡(52, 92)
- B≡(−52, 92)
Equation of a straight line passing through the point (4, 5) and equally inclined to the lines 3x=4y+7 and 5y=12x+6 is
9x−7y=1
9x+7y=71
7x+9y=73
7x−9y+17=0
- 74
- 2
- 52
- 72
- 21x+27y-131=0
- 21x-27y+131=0
- 99x-77y+51=0
- 99x+77y-51=0
- 11x-3y-17=0
- 11x+3y-17=0
- 3x+11y-19=0
- 3x-11y+19=0
The equation x- y = 4 and x2+4xy+y2=0 represent the sides of
an equilateral triangle
a right angled triangle
an isosceles triangle
none of these
- √32x+y=0
- x+√3y=0
- √3x+y=0
- x+√32y=0.
The equation of the bisectors of the angles between the lines represented by x2+2xycotθ+y2=0, is
x2−y2 = 0
x2−y2 = xy
(x2−y2)cotθ = 2xy
- x2−y2 = 3xy
- √32x+y=0
- x+√3y=0
- √3x+y=0
- x+√32y=0.
- x-7y+2=0
- 7x+y-2=0
- 2y-7x-5=0
- 2x+7y+5=0
- 11x-3y-17=0
- 11x+3y-17=0
- 3x+11y-19=0
- 3x-11y+19=0
- 21x+27y+131=0
- 99x−77x−51=0
- 99x−77x+51=0
- 21x+27y−131=0
- the equation of line BC is 7x−3y+4=0
- the equation of line BC is 7x+3y+4=0
- B≡(52, 92)
- B≡(−52, 92)
- √32x+y=0
- x+√3y=0
- √3x+y=0
- x+√32y=0.
- 9x−7y−41=0
- 7x+9y−3=0
- 9x+7y−3=0
- 9x−7y+41=0