Conjugate Hyperbola
Trending Questions
Q. The equation of a hyperbola, conjugate to the hyperbola x2+3xy+2y2+2x+3y+1=0, is
- x2+3xy+2y2+2x+3y+1=0
- x2+3xy+2y2+2x+3y+2=0
- x2+3xy+2y2+2x+3y+3=0
- x2+3xy+2y2+2x+3y+4=0
Q. The equation of the conjugate hyperbola of the hyperbola x2−2y2−2√5x−4√2y−3=0 is
- x2−2y2−2√5x−4√2y+2=0
- x2−2y2−2√5x−4√2y+5=0
- x2−2y2−2√5x−4√2y+3=0
- x2−2y2−2√5x−4√2y−2=0
Q. PQ is a double ordinate of the hyperbola x2a2−y2b2=1 such that OPQ is an equilateral triangle, O being the centre of the hyperbola, then the range of the eccentricity e of the hyperbola is
- e<4
- e≥2√3
- 1<e<2
- 1<e<√2
Q. If the angle between the asymptotes of hyperbola x2a2−y2b2=1 is π3. Then the eccentricity of conjugate hyperbola is
Q. PQ is a double ordinate of the hyperbola x2a2−y2b2=1 such that OPQ is an equilateral triangle, O being the centre of the hyperbola, then the range of the eccentricity e of the hyperbola is
- e≥2√3
- 1<e<2
- e<4
- 1<e<√2