Consistency of Linear System of Equations
Trending Questions
Q.
If is the set of distinct values of for which the following system of linear equations
has no solution, then is
an infinite set
a finite set containing two or more elements
a singleton set
an empty set
Q.
and are the parametric equations of
Q.
If x = cy + bz, y = az + cx, z = bx + ay where x, y, z are not all zeros, then the value of a2+b2+c2+2abc is
0
1
-1
None of these
Q. If the system of linear equations
2x+2y+3z=a
3x−y+5z=b
x−3y+2z=c
where a, b, c are non-zero real numbers, has more than one solution, then:
2x+2y+3z=a
3x−y+5z=b
x−3y+2z=c
where a, b, c are non-zero real numbers, has more than one solution, then:
- b+c−a=0
- b−c+a=0
- b−c−a=0
- a+b+c=0
Q. Let A=[abcd] and B=[pq]≠[00]. If AB=B and a+d=2, then the value of ad−bc is
Q. The number of non-trivial solutions of the system x−y+z=0, x+2y−z=0, 2x+y+3z=0 is
- 2
- 0
- 1
- infinite
Q. The system of equation ax+y+z=0, x+by+z=0;x+y+cz=0 has a non-trivial solution then 11−a+11−b+11−c=
- 2
- 0
- 1
- −1
Q. If the system of linear equations
x+ay+z=3
x+2y+2z=6
x+5y+3z=b
has no solution, then:
x+ay+z=3
x+2y+2z=6
x+5y+3z=b
has no solution, then:
- a=−1, b≠9
- a=1, b≠9
- a=−1, b=9
- a≠−1, b=9
Q. The number of all possible value(s) of k for which the system of equations kx+y+z=k−1, x+ky+z=k−1, x+y+kz=k−1 has no solution is
Q. Consider the system of equations
kx+(c−1)y+z=2
cx+(k+1)y+kz=4
x+cy+z=1
Then correct statement is/are
kx+(c−1)y+z=2
cx+(k+1)y+kz=4
x+cy+z=1
Then correct statement is/are
- If c=1, then the system will be inconsistent.
- If c=1, then the may have infinite solutions.
- If k=2cosπ5 then the system will be inconsistent.
- The system can never possess infinite solutions.
Q. If ω(≠1) is cube root of unity satisfying 1a+ω+1b+ω+1c+ω=2ω2 and 1a+ω2+1b+ω2+1c+ω2=2ω, then the value of 1a+1+1b+1+1c+1 is :
- 2
- ω
- −1
- −2
Q. If ω(≠1) is cube root of unity satisfying 1a+ω+1b+ω+1c+ω=2ω2 and 1a+ω2+1b+ω2+1c+ω2=2ω, then the value of 1a+1+1b+1+1c+1 is :
- 2
- ω
- −1
- −2
Q. Consider the system of equations
kx+(c−1)y+z=2
cx+(k+1)y+kz=4
x+cy+z=1
Then correct statement is/are
kx+(c−1)y+z=2
cx+(k+1)y+kz=4
x+cy+z=1
Then correct statement is/are
- If c=1, then the system will be inconsistent.
- If c=1, then the may have infinite solutions.
- If k=2cosπ5 then the system will be inconsistent.
- The system can never possess infinite solutions.