Cramer's Rule
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x + y + z = 6
x - y + z = 2 and
3x + 2y - 4z = -5
is
- x = 2, y = 1, z = 3
- x = 2, y = 3, z = 1
- x = 1, y = 3, z = 2
- x = 1, y = 2, z = 3
There are three values of t for which the following system of equations has non-trivial solutions.
(a-t) x+by + cz=0
bx + (c - t) y +az=0
cx + ay + (b-t) z=0
We can express the product of the three values of t in the form of determainant as
D
If D≠0 and at least one of D1, D2, D3 is not 0 then according to Cramer's rule the system of linear equations will have
non trivial solution
trivial solution
infinite solutions
no solutions
Let a, b, c, be any real numbers. Suppose that there are real numbers x, y, z not all zero such that x= cy +bz, y=az + cx and z = bx +ay. Then , a2 + b2+ c2+ 2abc is equal to
2
-1
0
1
px+y+z=px+py+z=px+y+pz=p
has no solution for
- three distinct values of p
- two distinct values of p
- only one value of p
- no such p exists
- A unique solution
- No solutions
- An infinite number of solutions
- Zero solution as the only solution
- Are in A.P.
- Are in G. P.
- Are in H. P.
- Satisfy a +2b + 3c = 0
x+y+z=5
x+2y+3z=9
x+3y+αz=β
has infinitely many solutions, then β−α equals:
- 5
- 18
- 8
- 21
If D≠0 and at least one of D1, D2, D3 is not 0 then according to Cramer's rule the system of linear equations will have
non trivial solution
trivial solution
infinite solutions
no solutions
Total number of solutions to the system of linear equations 2x + 3y + z = 1, 4X + 6y + 2z = 3, 6x + 9y + 3z = 2 is
If D=0 and at least one of D1, D2, D3 is not 0 then according to Cramer's rule the system of linear equations will have
non trivial solution
trivial solution
infinite solutions
no solutions
x+y+z=5
x+2y+3z=9
x+3y+αz=β
has infinitely many solutions, then β−α equals:
- 5
- 18
- 8
- 21
- a +b + c
- abc
- 1
- None of these
Which of the following cases will not lead to non trivial solutions in case of system of linear equations according to Cramer's rule Convention given D != 0 ?
D1 = 0, D2 = 0, D3 = 0
D1 = 0, D2 = 0, D3 != 0
D1 != 0, D2 != 0, D3 = 0
D1 != 0, D2 != 0, D3 != 0
- -1
- \N
- 1
- 2
x+2y+3z=1
3x+4y+5z=μ
4x+4y+4z=δ
is inconsistent?
- (4, 6)
- (3, 4)
- (1, 0)
- (4, 3)
If D=0 and at least one of D1, D2, D3 is not 0 then according to Cramer's rule the system of linear equations will have
non trivial solution
trivial solution
infinite solutions
no solutions
kx + 3y - z = 1; x + 2y + z = 2 and -kx + y + 2z = -1 have no solution, is
- k = -7
- k = 7
- k=−72
- k=72
The system of linear equations x+y=0, x–y=0, z=0 will have
non trivial solution
trivial solution
infinite solutions
no solutions
Total number of solutions to the system of linear equations 2x + 3y + z = 1, 4X + 6y + 2z = 3, 6x + 9y + 3z = 2 is 1
True
False
Total number of solutions to the system of linear equations x + y + 0.z = 0, X – y + 0.z = 0, X + 4y + 0.z = 0 is infinity.
True
False
- \N
- 1
- 2
- Infinite