Discriminant of a Quadratic Equation
Trending Questions
- 4
- 5
- 7
- 2
- a≤b
- a>b
- number of possible ordered pairs (a, b) is 3
- a<b
- 1
- −1
- −2
- 2
- a>0, b>0 and c<0
- b>0, c>0 and a<0
- a<0, b<0 and c>0
- b<0, c<0 and a>0
Find the discriminant of the quadratic equation 3x2−5x+2=0 and hence, find the nature of the roots.
1, two distinct real roots
−1, no real roots
−1, two distinct real roots
0, two equal roots
If α is a real root of the equation x3+px2+qx+r=0, where p, q and r are real. If p2−4q−2pα−3α2≥0 then other roots are ________.
Imaginary conjugate
Irrational conjugate
Real numbers
None of these
- (−∞, 4)
- (6, ∞)
- [4, 5]
- (5, 6]
- purely imaginary roots
- rational roots
- real roots
- roots of the form a+ib (a, b∈R, ab≠0)
- no real roots
- at least four real roots
- at least two real roots
- exactly six real roots
- −1
- 1
- −2
- 2
For the equation 3x2+px+3=0, p>0 one of the root is square of the other, then p is equal to
23
3
1
13
- 2
- 0
- 1
- −1
- [4, 5]
- (5, 6]
- (6, ∞)
- (−∞, 4)
- 1
- infinitely many
- 3
- 2
- D=96
- D=0
- D=−2
- D=4
- [1, 9]
- (7, 9]
- (10, ∞)
- [9, 10)
- at least two real roots
- no real roots
- exactly six real roots
- at least four real roots
Which of the following is only CORRECT Combination?
- (IV)→(P), (Q)
- (IV)→(P), (Q), (R)
- (III)→(P), (Q), (S)
- (III)→(P), (Q), (R)
- Roots of the equation are −1, −ca.
- One of the root is independent of the coefficients
- Both the roots are independent of the coefficients.
- Roots of the equation are −1, −2.
- Rational and equal
- Real and unequal
- Real and equal
- imaginary
- at least one equation has imaginary roots
- at least one equation has real roots
- Both the equations will have real roots
- Both the equations will have imaginary roots
- exactly six real roots
- at least two real roots
- at least four real roots
- no real roots
- −16
- 0
- 1
- 16
If α is a real root of the equation x3+px2+qx+r=0, where p, q and r are real. If p2−4q−2pα−3α2≥0 then other roots are ________.
Imaginary conjugate
Irrational conjugate
None of these
Real numbers
Reduce the expression y=x2−x+1x2+x+1 to the form ax2+bx+c and give condition for x to be real.
(y+1)2−4(y−1)2≥0
(y−1)2−2≥0
(y−1)2+4(y+1)2≥0
(y−1)2−4(y+1)2≥0