Equation of Normal for General Equation of a Circle
Trending Questions
Q. Let the tangent drawn at (−1, 2) to the circle x2+y2−3x−3y−2=0 is normal to the circle x2+y2−2ay+b=0. If the radius (r) of the second circle is such that [r]=1, then
([.] denotes the greatest integer function)
([.] denotes the greatest integer function)
- b∈[48, 49)
- b∈(45, 48]
- b∈(48, 49]
- b∈[45, 48)
Q. From a point P on the normal y=x+c of the circle x2+y2−2x−4y+5−k2=0, two tangents are drawn to the same circle touching it at point B and C. If the area of the quadrilateral OBPC (where O is the centre of the cicrle ) is 36 sq. units and ponit P is at a distance of |k|(√2−1) from the circle, then the possible value(s) of k is/are
- 6
- 6√2
- −6
- 4√2
Q. The equation of the normals to the circle x2+y2−8x−2y+12=0 at the points whose ordinate is −1 is/are
- 2x+y−9=0
- 2x−y−7=0
- 2x+y−7=0
- 2x−y−9=0
Q. If the line ax+by=2 is a normal to the circle x2+y2−4x−4y=0 and a tangent to the circle x2+y2=1, then
- a=12, b=12
- a=1−√72, b=1+√72
- a=14, b=34
- a=1, b=2
Q.
Find the equation of the normal to the circle x2+y2−6x−8y−24=0 at the point (4, 6).
2x -y = 2
3x + y = 18
3x - y = 12
-3y + 12 = 0
Q. If x + y + k = 0 is a tangent to the circle x2+y2 - 2x - 4y + 3 = 0 then k =
- ± 20
- –1, – 5
- ± 2
- 4
Q. The line 4x-3y=-12 is the tangent at point A(-3, 0) and the line 3x+4y=16 is the tangent at the point B(4, 1) to a circle. The equation of circle is
- (x+1)2+(y+3)2=25
- (x+1)2+(y−3)2=25
- (x−1)2+(y+3)2=25
- (x−1)2+(y−3)2=25
Q. Let the tangent drawn at (−1, 2) to the circle x2+y2−3x−3y−2=0 is normal to the circle x2+y2−2ay+b=0. If the radius (r) of the second circle is such that [r]=1, then
([.] denotes the greatest integer function)
([.] denotes the greatest integer function)
- b∈[48, 49)
- b∈(45, 48]
- b∈[45, 48)
- b∈(48, 49]
