Equation of Tangent in Slope Form
Trending Questions
If the tangent at to the curve touches the circle , then the value of is:
The equation of the tangents to the circle at the point whose abscissa is , are
None of these above
The equation of circle with centre and radius is
The circle C1:x2+y2=3 having centre at origin, O intersects the parabola x2=2y at the point P in the first quadrant. Let the tangent to the circle C1 at P touches other two circles C2 and C3 at R2 and R3, respectively. Suppose C2 and C3 have equal radii 2√3 and centres Q2 and Q3, respectively. If Q2 and Q3 lie on the Y-axis then
Q2Q3=12
R2R3=4√6
area of the ΔOR2R3 is 6√2
area of the ΔPQ2Q3 is 4√2
- 2√3y=−x−12
- 2√3y=12x+1
- √3y=3x+1
- √3y=x+3
The set of values of 'c' so that the equations y=|x|+c and x2+y2−8|x|−9=0 have no solution is
(∞, −3)∪(3, ∞)
(−3, 3)
(−∞, 5√2)∪(5√(2), ∞)
5√2−4, ∞
- −1
- 1
- −2
- 2
- 4π(3+√2)
- 8π(2−√2)
- 8π(3−2√2)
- 4π(2−√2)
- c2+7c+6=0
- c2−6c+7=0
- c2+6c+7=0
- c2−7c+6=0
- c2+7c+6=0
- c2−6c+7=0
- c2−7c+6=0
- c2+6c+7=0
- 20(x2+y2)−36x+45y=0
- 20(x2+y2)+36x−45y=0
- 36(x2+y2)−20y+45y=0
- 36(x2+y2)+20x−5y=0
- The equation of tangent at P is 5x+y+26=0
- The equation of tangent at Q is x+5y−26=0
- The point of intersection of tangents is (−132, 132)
- The mid-point of chord PQ is (2, −2)
A common tangent of the two circles is
- x=4
- y=2
- x+√3y=4
- x+2√2y=6
- 4x + 3y + 14 = 0, 4x + 3y + 16 = 0
- 4x – 3y – 24 = 0, 4x – 3y + 26 = 0
- x – y – 14 = 0, x – y + 16 = 0
- 4x – 3y + 34 = 0, 4x – 3y + 16 = 0
- 2ab4c−b2
- 2abb2−4ac
- 2abb2−4c
- 2ab4ac−b2
- 3x - 4y - 19 = 0, 3x - 4y + 31 = 0
- 4x + 3y - 19 = 0, 4x + 3y + 31 = 0
- 4x + 3y + 19 = 0, 4x + 3y - 31 = 0
- 3x - 4y + 19 = 0, 3x - 4y + 31 = 0
- a
- 2a
- 2√2a
- √3a
- y=x+3√2
- y=x+√2
- y=x−√2
- y=x−3√2
- 12m2 + 7m - 12 = 0
- 12m2 + 7m + 9 = 0
- 12m2 - 7m - 12 = 0
- 9m2 + 12m + 16 = 0
A tangent PT is drawn to the circle x2+y2=4 at the point P(√3, 1). A straight line L, perpendicular to PT is a tangent to the circle (x−3)2+y2=1
A possible equation of L is
- x−√3y=1
- x+√3y=1
- x−√3y=−1
- x+√3y=5
- ax−by=0
- ax+by=0
- bx−ay=0
- bx+ay=0
If O is the origin and OP, OQ are distinct tangents to the circle x2+y2+2gx+2fy+c=0, the circumcentre of the triangle OPQ is
- (-g, -f)
- (g, f)
- (-f, -g)
- None of these
- angle between the tangents is π2
- equation of one of the two tangents is x−2y−5=0
- one of the two tangents passes through the origin
- sum of the squares of the slopes of the two tangents is 154