Equation of a Sphere : Diametric Form
Trending Questions
Q.
Find the equation of a sphere, whose end points of a diameter are (0, 0, 0) and (1, 2, 3)
x2+y2+z2−x−2y−3z=0
x2+y2+z2−2x−y−3z=0
x2+y2+z2−3x−2y−z=0
x2+y2+z2−x−2y−z=0
Q. If (2, 3, 5) is one end of a diameter of the sphere x2+y2+z2−6x−12y−2z+20=0 then co-ordinates of the other end of the diameter are
- (4, 3, 5)
- (4, 9, -3)
- (4, 9, 3)
- (4, 3, -3)
- (4, 9, 5)
Q. Find the equation of the sphere having extremities of one of its diameters as the
points (2, 3, 5) and (-4, 7, 11).
points (2, 3, 5) and (-4, 7, 11).
- x2+y2+z2−2x−10y−16z+68=0
- x2+y2+z2+2x−10y−16z=68
- x2+y2+z2+2x−10y−16z+68=0
- x2+y2+z2+2x+10y+16z+68=0
Q.
Find the equation of a sphere, whose end points of a diameter are (0, 0, 0) and (1, 2, 3)
x2+y2+z2−x−2y−3z=0
x2+y2+z2−2x−y−3z=0
x2+y2+z2−3x−2y−z=0
x2+y2+z2−x−2y−z=0
