General Solution of Trigonometric Equation
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Q.
Prove that:
Q.
If and , then
Q.
The maximum value of is:
Q.
If , then
Q. General solutions of the equation cos3x=sin2x is
- {2nπ5−π10}∪{2nπ+π2}, n∈Z
- {2nπ5−π10}∪{2nπ−π2}, n∈Z
- {2nπ5+π10}∪{2nπ+π2}, n∈Z
- {2nπ5+π10}∪{2nπ−π2}, n∈Z
Q.
The number of solution of is
Infinite
No solution
Q.
The number of values of satisfying the equation is
Q.
If and are the roots of , then the equation, whose roots are and
Q.
The complete solution set of the inequality [cot−1x]2−6[cot−1x]+9≤0, where [.] denotes greatest integer function is
- (−∞, cot2)
- (−∞, cot3)
- (cot2, cot3)
- (cot2, ∞)
Q. In a △ ABC, if c2+a2−b2=ac, then ∠B=
[MP PET 1983, 89, 90]
[MP PET 1983, 89, 90]
- π6
- π4
- π3
- None of these
Q. General solution of the equation tan5x=cot5x is :
- nπ±π20, n∈Z
- nπ5+π20, n∈Z
- nπ5±π4, n∈Z
- nπ5±π20, n∈Z
Q. The value of x in the interval [0, 2π] for which 4sin2x−8sinx+3≤0 is
- [π6, π2]
- [π3, π2]
- [π6, 3π2]
- [π6, 5π6]
Q.
If is monotonically increasing for all , then
None of these
Q. The general solution(s) of the equation sec4θ−sec2θ=2 can be
- (2n+1)π12, n∈Z
- (2n+1)π10, n∈Z
- (2n+1)π2, n∈Z
- (2n+1)π4, n∈Z
Q.
If and , then the value of in terms of and is:
Q. The solution set of the equation sin3x+cos2x=−2 is
(where n∈Z)
(where n∈Z)
- (2n+1)π2
- (4n−1)π2
- (2n−1)π2
- (4n+1)π2
Q.
Solve
Q. If sin−1(sinp)=3π−p and the point of intersection of the lines x+y=6 and px−y=3 will have integral co-ordinates (both abscissa and ordinate), then the number of values of p is
Q. The number of solution(s) of the equation esinx−e−sinx=4, (e≈2.72) is
- 0
- 1
- 2
- 4
Q. General solution of the equation tanx+tan2x+√3tanxtan2x=√3 is :
- nπ3+π9, n∈Z
- nπ+π9, n∈Z
- nπ−π9, n∈Z
- nπ2+π3, n∈Z
Q. The range of k for which the equation kcosx−3sinx=k+1 has a solution is
- (−∞, 4]
- (−∞, 4)
- (4, ∞)
- [4, ∞)
Q. The general solution(s) of θ which satisfy 3−2cosθ–4sinθ−cos2θ+sin2θ=0 is/are (where n∈Z)
- 2nπ
- 2nπ+π2
- 2nπ−π2
- nπ+π3
Q. The general solutions for the equation cos4x=√5+14 is
- x=nπ±π20, n∈Z
- x=nπ2±π40, n∈Z
- x=nπ4±π20, n∈Z
- x=nπ2±π20, n∈Z
Q. The number of ordered pairs (x, y) satisfying the equation x2+2xsin(xy)+1=0 is
(where y∈[0, 2π])
(where y∈[0, 2π])
- 1
- 2
- 3
- 0
Q. Consider the trigonometric equation tanx(sin2x+1)=sinx(2+tanx). The number of solution(s) of the equation in (0, 4π) is
Q. General solutions of x for which 2sinx+1=0 is :
- nπ+(−1)n(−π6), n∈Z
- nπ±(−1)n2π3, n∈Z
- nπ±π3, n∈Z
- nπ±(−1)n(−π6), n∈Z
Q. If tana, tanb, tanc, tand are the roots of the eqn tan(45°+θ)=3tan3θ, then
1tana+1tanb+1tanc+1tand is
1tana+1tanb+1tanc+1tand is
Q. If [sinx]+[√2cosx]=−3, (where [.] represents the greatest integer function), then x belongs to
- [π, 5π4)
- (π, 5π4)
- [π, 5π4]
- no solution
Q. If cosx+cosy+cosz=0=sinx+siny+sinz, then
- cosx−y2=±√32
- cosx−y2=±12
- sin2x−y2=34
- tanx−y2=±1√3
Q.
If 3sinx+4cosax=7 has atleast one solution, then 'a' has to be necessarily _______.
- irrational number
- rational number
- even integer
- odd integer