General Solution of a Differential Equation
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Q.
Which of the following is the solution of the differential equation with initial condition ?
Q. General solution of a differential equation is y=kex. Find the particular solution if the curve passes through (0, 1)
- y=kex
- y=kex+C
- y=ex
- y=2ex
Q. General solution of a differential equation is y=kex. Find the particular solution if the curve passes through (0, 1)
- y=kex
- y=kex+C
- y=ex
- y=2ex
Q. Which of the following relation in x and y is general solution of the differential equation dydx=y
- y=ex
- y=ex+c
- y=kex
- y=kex+c
Q. The solution of (y(1+x−1)+siny)dx+(x+logx+x cosy)dy=0 is
- (1+y−1siny)+x−1logx=C
- (y+siny)+xy log x=C
- xy+ylogx+x sin y=C
- None of these
Q. Solution of 2ysinxdydx=2sinx⋅cosx−y2cosx, x=π2, y=1 is given by
- y2=sinx
- y=sin2x
- y2=cosx+1
- None of these