Homogenization
Trending Questions
Q. Let PQ be a chord of the ellipse x2a2+y2b2=1 which subtends right angle at the centre (0, 0). Then its distance from the centre is equal to
- ab√a2+b2
- a√a2+b2
- b√a2+b2
- 2ab√a2+b2
Q.
The equation of pair of straight lines joining the point of intersection of the curve x2+y2=4 and y - x = 2 to the origin, is
x2+y2=(y−x)2
x2+y2+(y−x)2=0
x2+y2=4(y−x)2
x2+y2+4(y−x)2=0
Q. If the curve x2+2y2=2 intersects the line x+y=1 at two points P and Q, then the angle subtended by the line segment PQ at the origin is:
- π2+tan−1(14)
- π2−tan−1(14)
- π2+tan−1(13)
- π2−tan−1(13)
Q. If the line xa+yb=1 intersects the curve 5x2+5y2+5bx+5ay−9ab=0 at P and Q such that ∠POQ=90∘, where O is the origin, then the value of ab is
- 12
- 2
- 13
- 3
Q.
The equation of pair of straight lines joining the point of intersection of the curve x2+y2=4 and y - x = 2 to the origin, is
x2+y2=(y−x)2
x2+y2+(y−x)2=0
x2+y2=4(y−x)2
x2+y2+4(y−x)2=0
Q. Let PQ be a chord of the ellipse x2a2+y2b2=1 which subtends right angle at the centre (0, 0). Then its distance from the centre is equal to
- ab√a2+b2
- a√a2+b2
- b√a2+b2
- 2ab√a2+b2
Q. A pair of perpendicular straight lines passing through the origin also passes through the points of intersection of the curve x2+y2=4 with the line x+y=a, then value(s) of a can be
- 2
- 3
- −2
- −3
Q. The asymptotes of the curve x2+4xy+3y2+4x−3y+1=0 passes through a fixed point (h, k) then h+k is
Q. If the angle between the pair of straight lines formed by joining the points of intersection of x2+y2=4 and y=3x+c to the origin is right angle, then c2=
Q. The equation of the lines represented by 4x2+24xy+11y2=0 is/are
- 2x+y=0
- 2x+11y=0
- x−y=0
- y−2x=0
Q. A pair of perpendicular straight lines passing through the origin also passes through the points of intersection of the curve x2+y2=4 with the line x+y=a, then value(s) of a can be
- 2
- 3
- −2
- −3