How to Find the Inverse of a Function
Trending Questions
Q. The inverse of the function is f(x)=10x−10−x10x+10−x+1 is
- f−1(x)=log10x2−x
- f−1(x)=12log10x2−x
- f−1(x)=12log10x1−x
- None of these
Q. The inverse function of f(x)=82x−8−2x82x+8−2x, x∈(−1, 1), is
- 14(log8e)loge(1−x1+x)
- 14(log8e)loge(1+x1−x)
- 14loge(1+x1−x)
- 14loge(1−x1+x)
Q. If f(x)=(x−2)3 is a function defined in R→R, then
- f−1(x)=3√x−2
- f−1(x) does not exist
- f−1(x)=(−x−2)3
- f−1(x)=3√x+2
Q. Let f:R→R be defined as f(x) = 10x + 7. The function g:R→R such that gof = fog =IR. Then g(2017) =
Q. Let f:R→R be defined by f(x)=(ex−e−x)2.
The inverse of the given function is:
The inverse of the given function is:
- f−1(x)=loge(x+√x2+1)
- f−1(x)=loge(x−√x2−1)
- f−1(x)=loge(x−√x2+1)
- f−1(x)=loge(x+√x2−1)
Q.
The inverse of f(x)=(5−(x−8)5)13 is
5−(x−8)5
8+(5−x3)15
8−(5−x3)15
(5−(x−8)15)3
Q. Let f(x)=(x+1)2−1, (x≥−1). Then the set S={x:f(x)=f−1(x)}. is
- Empty
- {0, −1}
- {0, 1, −1}
- {0, −1, −3+i√32, −3−i√32}
Q. If f:(12, ∞)→R defined as f(x)=log5(2x−1), then f−1(x)=
- 12(5x+1)
- 2x+1
- 5x+1
- 15(2x+1)
Q. If the function f:[1, ∞)→[1, ∞) is defined by f(x)=2x(x−1), then f−1(x) is
- (12)x(x−1)
- 12(1+√1+4 log2 x)
- 12(1−√1+4 log2 x)
- not defined
Q. Let f:R−(35}→R−(35} be defined by f(x)=3x+25x−3.
Then
Then
- f−1(x)=f(x)
- f−1(x)=−f(x)
- fof(x)=−x
- f−1(x)=119f(x)
Q. The inverse of the function is f(x)=10x−10−x10x+10−x+1 is
- f−1(x)=log10x2−x
- f−1(x)=12log10x2−x
- f−1(x)=12log10x1−x
- None of these
Q. Let f(x)=x2−x+1, x≥12 then the solution of the equation f−1(x)=x is
- x = 1
- x = 2
- x=12
- None of these
Q. Suppose f(x) = (x+1)2 for ≥ -1. If g(x) is the function whose graph is reflection of the graph of f(x) with respect to line y = x, then g(x) equals
- −√x−1, x≥0
- 1(x+1)2, x>−1
- √x+1, x≥−1
- √x−1, x≥0